Question

To solve the sustem of equations below, kira isolated variable y in the first equation then sybstituted it into the second equation.what was the resulting equation? 3y=12x, x^2+y^2=81

Answer 1

Answer:

Resulting equation is

$x^2+\left(4x\right)^2=81$

Step-by-step explanation:

Isolate y in the  first equation $3y=12x$

divide both sides by 3

$y=4x$

Now we substitute this value of y into second equation

$x^2+y^2=81$

$x^2+\left(4x\right)^2=81$

Hence the resulting equation is

$x^2+\left(4x\right)^2=81$

Notice that question doesn't says to solve so there is no need to simplify or solve that equation further

Answer 2

Answer:

$x^2+(4x)^2=81$  or $x^2+16x^2=81$   or $17x^2=81$  

Step-by-step explanation:

Given : $3y=12x$

            $x^2+y^2=81$

To Find: Kira isolated variable y in the first equation then substituted it into the second equation.what was the resulting equation?

Solution:

$3y=12x$   --1

$x^2+y^2=81$  --2

Value of y from 1

$y=4x$

Substitute this value of y in 2

$x^2+(4x)^2=81$  

$x^2+16x^2=81$  

$17x^2=81$  

Hence  the resulting equation is $x^2+(4x)^2=81$  or $x^2+16x^2=81$   or $17x^2=81$