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3 years ago

Solve the System and write the solution as an ordered pair. 3x+3y=6 5x-6y=15

Mathematics

2 answers:

Ugo [173]3 years ago

4 0

$\\ \sf\longmapsto 3x+3y=6\dots(1)$

$\\ \sf\longmapsto 5x-6y=15\dots(2)$

Multiply eq(1) by 2 and eq(2) by 1

$\\ \sf\longmapsto 6x+6y=12$

$\\ \sf\longmapsto 5x-6y=15$

$\\ \sf\longmapsto 11x=27$

$\\ \sf\longmapsto x=\dfrac{27}{11}$

Now

Put in eq(1)

$\\ \sf\longmapsto 3\dfrac{27}{11}+3y=6$

$\\ \sf\longmapsto \dfrac{81}{11}+3y=6$

$\\ \sf\longmapsto 3y=6-\dfrac{81}{11}$

$\\ \sf\longmapsto 3y=\dfrac{66-81}{11}$

$\\ \sf\longmapsto 3y=\dfrac{15}{11}$

$\\ \sf\longmapsto y=\dfrac{15}{33}$

mel-nik [20]3 years ago

3 0

Answer:

(-3, 5)

Step-by-step explanation:

Given system:

3x+3y=6
5x-6y=15

Simplify the first equation by dividing all terms by 3:

3x/3 + 3y/3 = 6/3
x + y = 2
x = 2 - y

Substitute x into the second equation:

5(2 - y) + 6y = 15
10 - 5y + 6y = 15
y = 15 - 10
y = 5

Find x:

x = 2 - 5
x = -3

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