The first step to solving this expression is to factor out the perfect cube
![\sqrt[3]{m^{2} n^{3} X n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bm%5E%7B2%7D%20%20n%5E%7B3%7D%20X%20n%5E%7B2%7D%20%20%20%7D%20)
The root of a product is equal to the product of the roots of each factor. This will make the expression look like the following:
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%20%7D%20)
Finally,, reduce the index of the radical and exponent with 3
n
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%20%7D%20)
This means that the correct answer to your question is n
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%7D%20)
.
Let me know if you have any further questions
:)
Answer: the area is 20 square centimeters.
Step-by-step explanation:
The area of an arc of angle x in a circle of radius r is:
A = (x/3.14)*3.14*r^2 = x*r^2
here we have x = (4/5)*3.14 and r = 5cm
Then the area is:
A = (4/5)*(5cm)^2 = 20cm^2
Agile asertation anigaa man aqaani sa lo samaayo
Answer:
I'm not sure how to answer is but i think its called < CDE or < EDC or it is an acute angle.
Step-by-step explanation:
The ones that match are
1 and 5
2 and 6
7 and 3
8 and 4