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Andrew [12]
2 years ago
8

Please find the value of this one expression

Mathematics
1 answer:
Masja [62]2 years ago
3 0

Answer:

Solving the expression \frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2) we get 6

The answer is 6.

Step-by-step explanation:

We need to find value of expression: \frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)

We know that \sqrt{81}=9

Our expression will become

\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{9 } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-2 -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-4)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4

We can write \sqrt[6]{8}=(2^3)^{\frac{1}{6}}=(2)^{\frac{3}{6}}=2^\frac{1}{2}=\sqrt{2}  \\

Now, replacing \sqrt[6]{8}=\sqrt{2}

=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4\\=\frac{2}{\sqrt{2} }.\sqrt{2}+4\\=2+4\\=6

So, solving the expression \frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2) we get 6

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The first step to solving this expression is to factor out the perfect cube
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