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earnstyle [38]
3 years ago
8

What is the area of polygon PQRS?

Mathematics
2 answers:
PolarNik [594]3 years ago
3 0

Where are the answers?

Step-by-step explanation:

Ksju [112]3 years ago
3 0
1) starting with the rectangle 6*15 which is 90 (that’s the area for it)

2) take 8*17 for the triangle which is 136 and divide it by two 136/2 and you’ll get 68 (that’s the second area)

3) add them together to get the full area 68+90=158
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Help please with manipulating fractions URGENT!!!!!!!!!!
almond37 [142]

Answer:

1: x=y-3    linear equation : y=x+3

2:y=-2x-3  linear equation : y=-2x-3

3: -4y+6 =2 linear equation : y=2-6/-4 ⇒ y=1

4:2/3 x-1/3y=2 , linear equation : y=2x-6

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13: 5x+25=y² not linear

y = √5x+25

14 : 8+y=4x linear y=4x-8

15: 9xy-6x=7 not linear

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3 0
3 years ago
Consider the functions graphed below.
Reptile [31]

Answer:

it's A

Step-by-step explanation:

4 0
3 years ago
Help me Ill give brainlist
IrinaVladis [17]

Answer:

18π + 90

Step-by-step explanation:

The perimeter is the sum of quarter of the circumference and 2r , that is

P = 2πr + (45 + 45)

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7 0
3 years ago
Which of the following shapes are used to compose this figure?
attashe74 [19]
Parallelogram is the correct answer
5 0
4 years ago
Read 2 more answers
We are interested in conducting a study to determine the percentage of voters of a state would vote for the incumbent governor.
nexus9112 [7]

Answer:

The minimum sample size is N=1537.

Step-by-step explanation:

We want to know the sample size to estimate the proportion of voters with a margin of error of 0.05, with a 95% of confidence.

The margin of error can be defined as:

e=UL-LL=(p+z*\sqrt{\frac{p(1-p)}{N}}) -(p-z*\sqrt{\frac{p(1-p)}{N}})=2z\sqrt{\frac{p(1-p)}{N}}

We can calculate N from this

e=2z\sqrt{\frac{p(1-p)}{N}}\\\\\frac{p(1-p)}{N}=(\frac{e}{2z})^2\\\\N= (\frac{2z}{e})^2*p(1-p)

The sample size will be calculated for p=0.5, which is the proportion that requires the larger sample size (maximum variance).

The z-value for a 95% CI is z=1.96.

The minimum sample size is then

N= (\frac{2z}{e})^2*p(1-p)=(\frac{2*1.96}{0.05})^2*0.5(1-0.5)=6146.56*0.5*0.5=1536.64

The minimum sample size is N=1537.

8 0
3 years ago
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