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Ber [7]
3 years ago
12

What is the slope- intercept equation of the line below?

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0

Answer:

y= 5/4x - 2

Step-by-step explanation:

Hey!

<u>Slope-Intercept Form</u> is y = mx + b, where <u>m</u> is the <u>slope</u> and <u>b</u> is the <u>y-intercept.</u>

First we can <em>locate the y-intercept</em>, or where the line passes through the y-axis.

The y-intercept is -2.

<em>Substitute </em>in the Slope-Intercept Form Equation:

y = mx -2

<u>Pick another point and substitute its x and y values in this equation.</u>

I chose (5,2) and substituted as 2 = m(5) -2

<em>Isolate </em>m:

<em>Add </em>2 to both sides <u>[Addition Property of Equality</u>]

2 + 2 = 5m - 2 + 2

4 = 5m

<em>Divide </em>by 5<em> </em>on both sides. [<u>Division Property of Equality</u>]

5m/5 = 4/5

m=4/5

<em>Substitute </em>in Slope-Intercept Form Equation.

<u><em>The Equation in Slope Intercept Form is y = 4/5x - 2</em></u>

==================================================================

<em>Hope I helped, Feel Free to ask any questions to clarify :) </em>

<em> Have a fantastic day! </em>

<em>                        -Aadi x</em>

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Evaluate the line integral, where c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)
Arada [10]

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<h3>What is integration?</h3>

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

The parametric equations for the line segment from (0, 0, 0) to (2, 3, 4)

x(t) = (1-t)0 + t×2 = 2t  

y(t) = (1-t)0 + t×3 = 3t

z(t) = (1-t)0 + t×4 = 4t

Finding its derivative;

x'(t) = 2

y'(t) = 3

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The line integral is given by:

\rm \int\limits_C {xe^{yz}} \, ds = \int\limits^1_0 {2te^{12t^2}} \, \sqrt{2^2+3^2+4^2} dt

 

\rm ds = \sqrt{2^2+3^2+4^2} dt

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\rm \int\limits_C {xe^{yz}} \, ds = \dfrac{\sqrt{29}}{12}  (e^{12}-1)   or

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Learn more about integration here:

brainly.com/question/18125359

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On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.


-2x+3y=-6                 Add 2x in both sides
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The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.

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4 years ago
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