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kondaur [170]
3 years ago
5

Find the distance between the two points rounding to the nearest tenth (if necessary). (−2,−2) and (0,7)​

Mathematics
1 answer:
pogonyaev3 years ago
7 0

Answer:

9 units

Step-by-step explanation:

(0,7)-(-2,-2)= (2,9)

distance = 9 units

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What is (6)(-7)? Please help fast
Degger [83]

Answer:

-42 is the answer for the question

3 0
3 years ago
What is the solution of the following system of equations?<br> 2x + y = -7<br> -3x - 2y = 10
pentagon [3]

Answer:

the solution is    (-4, -3)

Step-by-step explanation:

Multiply the first equation by 2.  This produces 4x + 2y = -14.

Now combine this result with the second equation:

4x + 2y = -14

-3x - 2y = 10

------------------

 x          = -4

Subbing -4 for x in the first equation yields 2x - 4 = -7, or 2x = -3.  

Then x = -3/2, and the solution is    (-4, -3)

8 0
3 years ago
Evaluate 3x for x = -2, x = 1, and x = 3.
jok3333 [9.3K]

Answer:

A) 1/9, 3, 27

Step-by-step explanation:

i think you mean 3^x (and not 3x).

because otherwise none of the answer options withdraw makes any sense.

3^-2 = 1/(3²) = 1/9

3¹ = 3

3³ = 27

3 0
2 years ago
There are 18 gallons of gas in a car at the
GREYUIT [131]

Answer:

18/2.5 = 7.2

Step-by-step explanation:

Since there are 18 gallons at the beginning of the trip you divide by 2.5 to find out how much gas is left after each hour.

7 0
2 years ago
Ronald Sutter, an assembly line worker, earns $16.655 per hour. He typically works 36.225 hours per week. What is his usual stra
Nadusha1986 [10]

His usual straight-time pay is $603.327375 per week

<h3>How to determine his usual straight-time pay?</h3>

The given parameters are

Rate = $16.655 per hour

Duration = 36.225 hours per week

His usual straight-time pay is calculated as

Usual pay = Rate * Duration

So, we have

Usual pay = $16.655 per hour * 36.225 hours per week

Evaluate the product

Usual pay = $603.327375 per week

Hence, his usual straight-time pay is $603.327375 per week

Read more about linear rates at

brainly.com/question/7040405

#SPJ1

7 0
2 years ago
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