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2 years ago

SUBTRACT the following POLYNOMIALS (96−74+92)−(56−104+42) plzzzzz and show work

Mathematics

1 answer:

xz_007 [3.2K]2 years ago

7 0

Answer:

120

Step-by-step explanation:

So What I did 1st was do the math for (96−74+92) so I got 114

Then I did that the same with (56−104+42) so I got -6

Then All I had was 114-(-6) then I removed the parentheses then I made the equation 114+6 So I calculated that and got 120

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Step-by-step explanation:

90° and two circles can pass through a given point

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LeBron flips a coin 3 times. What is the probability of LeBron getting tails AT LEAST twice in a row? (Note: If he gets tails mo

madam [21]

Answer:

3 / 8

Step-by-step explanation:

From the tree diagram provided :

Required outcome = atleast two consecutive tails :

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2 years ago

A right triangle's height is 3 times the length of its base. if the area of the triangle is 486, what is the height?

Irina-Kira [14]

The formula of the area of a triangle:
$A_\Delta=\dfrac{bh}{2}$
b - the bash - the height
We have:
b - the base3b - the height486 - the area

Substitute:
$\dfrac{3b\cdot b}{2}=486\ \ \ |\cdot2\\\\3b^2=972\ \ \ |:3\\\\b^2=324\to b=\sqrt{324}\\\\b=16\to h=3b=3\cdot18=54$
Answer: The length of the height is equal 54 units.

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2 years ago

One polygon has a side of length 2 feet. A similar polygon has a corresponding side of length 4 feet. The ratio of the

Gennadij [26K]

The answer to your question is 2/1

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2 years ago

Jay factored the 4 term polynomial : x^3 - 9x +2x^2 - 18 and decided that the complete factorization was : ( x + 2 ) (x^2-9 ). B

labwork [276]

Answer:

$x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

Step-by-step explanation:

we are given that $x^3-9x+2x^2-18$

w are sked to step by step factorise the above polynomial

$\left(x^3+2x^2\right)+\left(-9x-18\right)$

$-9\mathrm{\:from\:}-9x-18\mathrm{:\quad }-9\left(x+2\right)$

$-9x-9\cdot \:2$

$-9\left(x+2\right)$

$\mathrm{Factor\:out\:}x^2\mathrm{\:from\:}x^3+2x^2\mathrm{:\quad }x^2\left(x+2\right)$

$-9\left(x+2\right)+x^2\left(x+2\right)$

$\left(x+2\right)\left(x^2-9\right)$

$x^2-9:\quad \left(x+3\right)\left(x-3\right)$

$x^2-9$

$\mathrm{Rewrite\:}9\mathrm{\:as\:}3^2$

$=x^2-3^2$

$\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$

$x^2-3^2=\left(x+3\right)\left(x-3\right)$

Hence

$x^3-9x+2x^2-18=\left(x+2\right)\left(x+3\right)\left(x-3\right)$

a) The jay mistake was he did not factorise $x^3-9x+2x^2-18x^2-9 furtherb) the complete answer wil be [tex]x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

8 0

2 years ago

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