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pickupchik [31]
3 years ago
5

Seventh grade > L.8 Solve percent equations: word problems JS6

Mathematics
1 answer:
ladessa [460]3 years ago
4 0
30% diet and 10 regular not shoreee
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Nick has tennis practice every sixth day. Mark has tennis practice every 4th day. On July 31st they both had tennis practice. Wh
Montano1993 [528]

Nick has tennis practice every sixth day = 6

Mark has tennis practice every 4th day = 4

They both had tennis practice on = 31st July

We have to find when will be the next time that they both have practice on the same day?

For this, we will find the LCM of 4 and 6

So, LCM of 4 and 6 is 12.

So, it will be 12 days after 31st July, that they will practice on the same day.

So it is 12th August.


3 0
4 years ago
Janet bought a book for $19.95, and the tax was 6.25%. including tax how much did she pay round to nearest cent​
drek231 [11]

Answer:$21.2

Step-by-step explanation:

multiply 19.25*6.25 then divide by 100 then add that answer onto 19.25 to then get an estimate of 21.2 dollars

3 0
3 years ago
Can someone help me find X
bearhunter [10]

Answer:

x = 122 degrees

Step-by-step explanation:

6 0
3 years ago
One positive number is one-fifth of another number. the difference of the two numbers is 84. find the numbers.
seraphim [82]
Answer:  The numbers are:  " 21 " and " 105 " .
___________________________________________________
Explanation:
___________________________________________________
Let "x" be the "one positive number:

Let "y" be the "[an]othyer number".

x = 1/5 (y)
___________________________________________________
Given that the difference of the two number is "84" ;  and that "x" is (1/5) of  "y" ;  we determine that "x" is smaller than "y".

So, y − x = 84 .

Add "x" to each side of this equation; to solve for "y" in terms of "x" ;

y − x + x = 84 + x  ;

 y = 84 + x ;
___________________________________________________
So, we have: 

 x = (1/5) y ;

and:  y = 84 + x  ;

Substitute "(1/5)y" for "x" ;  in  "y = 84 + x " ;  to solve for "y" ;

 y = 84 + [ (1/5)y ]

Subtract  " [ (1/5)y ] " from EACH SIDE of the equation ;

y − [ (1/5)y ] = 84 + [ (1/5)y ] −  [ (1/5)y ]  ;

to get:

  [ (4/5)y ] = 84 ;


       ↔    (4y) / 5 = 84  ;
      
        →  4y = 5 * 84  ;

      Divide EACH SIDE of the equation by "4" ; 
to isolate "y" on one side of the equation; and to solve for "y" ;

           4y / 4 = (5 * 84) / 4 ;

                 y =  5 * (84/4) = 5 * 21 = 105 .

   y = 105 .
___________________________________________________
Now, plug "105" for "y" into:
___________________________________________________
Either:
___________________________________________________
 x = (1/5) y ;

OR:

  y = 84 + x  ;
___________________________________________________
to solve for "x" ;
___________________________________________________
Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
___________________________________________________
Start with:

x = (1/5)y 

    →  (1/5)*(105) = 105 / 5 = 21 ;  x = 21 ; 

___________________________________________________
So, x = 21;  y = 105 .
___________________________________________________
Now, let us see if this values hold true in the other equation:
___________________________________________________
y = 84 + x ;

105 = ? 84 + 21 ?
 
105 = ? 105 ? Yes!
___________________________________________________
The numbers are:  " 21 " and  "105 " .
___________________________________________________

6 0
3 years ago
IF the area of the frame was 64inches², what would be 2 possible sets of dimensions that could be used to make a frame with that
alina1380 [7]
To resolve this exercise you have to choose two numbers that when you multiply them, you get 64:
 
 For Set 1: If you choose to make a square frame, you can calculate its dimensions by clearing the value of each sides of it from the formula of the area of a square:

 A= L²
 L= √A
 L= √64 inches²
 L= 8 inches
 
 So, you have a square frame of 8 inches x 8inches = 64 inches²

 Set 1: 8 inches x 8 inches

 For set 2, you can make a rectangular frame with the following dimensions: 16 inches x  4 inches = 64 inches²

 Set 2: 16 inches x  4 inches
7 0
3 years ago
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