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icang [17]
3 years ago
5

Please help i only have 20 minuets

Computers and Technology
1 answer:
Ann [662]3 years ago
7 0

Answer:

Newton's first law states that an object will stay at rest or be in motion, unless an unbalanced force acts on it.

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Is it ok to give a website your zip code?
Salsk061 [2.6K]
When a website takes in personal information from a user, the owners of the website have no idea what was input, no matter how hard they tried. The information is not stored, and is used by Javascript APIs to locate your address to either ensure that it is valid, or so that you can choose your address.

It's completely safe, and if a website looks really, really sketchy, then just don't give them anything personal.

Another way to identify if a website is safe to give your personal information to is if you see "HTTPS" in the URL at the top of your browser. This means Hyper Text Transfer Protocol Secure, and is the protocol used to transfer information over the internet SECURELY, via encryption that only computers are able to decrypt, and will not show that information to owners of the server/website.
5 0
3 years ago
Suppose list1 is an MyArrayList and list2 is a MyLinkedList. Both contains 1 million double values. Analyze the following code:
hjlf

Answer:

The correct answer for the given question is " The Code fragment A runs fastly than the code fragment of B".

Explanation:

In this question there are some information is missing i. e options. The question does not give any options. The options for the given question is given below

(A.) The Code fragment A runs fastly than the code fragment of B.

(B.) The Code fragment B runs fastly than code fragment of  A.

(C)  The Code fragment A runs as fastly as code fragment of B.  

So we conclude the answer i.e option(A) because As given in the question list1  is a MyArrayList and list2 is a MyLinkedList.  , in list1 we fetching the data easily and fastly means that it remove the data easily as compare to list2 As MyArrayList is storing the list only and also we can fetch the data easily manner.

The list2 is an object of MyLinkedList means that it manipulating the data fastly as compared to MyArrayList but if we compared the fetching of data then  MyArrayList is a better option so the code fragment runs fastly then code fragmented B.

7 0
3 years ago
The function known as "Comments" can be displayed during a presentation<br>O True<br>False​
Sonja [21]

Answer:

false

Explanation:

Select the comment icon. on the slide. The Comments pane will open and you can see comments for that slide.

Select Reply to respond to a comment.

Select the Next or Back buttons to go between comments and slides.

3 0
4 years ago
Read 2 more answers
If a wire has insulation that allows it to operate in a temperature of up to 194 degrees Fahrenheit, what temperature will the w
zzz [600]
(194°F-32)×5/9
= 90°C
therefore the answer is 90degrees Celcius
6 0
4 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
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