Lower range tones generally require larger speakers.
It's no secret that lower range tones generally require larger speakers. This is because lower frequencies have longer wavelengths, and thus require more physical space to produce.
While this may seem like a simple concept, there are a few things to keep in mind when it comes to speaker size and low frequency response. First, larger speakers can usually reproduce lower frequencies more efficiently than smaller ones. Second, the size of the speaker's enclosure also plays a role in how well it can reproduce low frequencies.
A larger enclosure will typically have an easier time reproducing low frequencies than a smaller one.
Keep these things in mind when selecting speakers for your system. If you're looking for accurate low frequency reproduction, make sure to choose speakers with larger drivers and enclosures.
Learn more on speakers here:
brainly.com/question/14649463
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Explanation:
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Answer:
#include <iostream>
using namespace std;
void swap(int *a,int *b){ //function to interchange values of 2 variables
int temp=*a;
*a=*b;
*b=temp;
}
void sort(int queue[],int n)
{
int i,j;
for(i=0;i<n;i++) //to implement bubble sort
{
for(j=0;j<n-i-1;j++)
{
if(queue[j]>queue[j+1])
swap(queue[j],queue[j+1]); //to swap values of these 2 variables
}
}
}
int main()
{
int queue[]={6,4,2,9,5,1};
int n=sizeof(queue)/4; //to find length of array
sort(queue,n);
for(int i=0;i<n;i++)
cout<<queue[i]<<" ";
return 0;
}
OUTPUT :
1 2 4 5 6 9
Explanation:
In the above code, Queue is implemented using an array and then passed to a function sort, so that the queue can be sorted in ascending order. In the sort function, in each pass 2 adjacent values are compared and if lower index value is greater than the higher one they are swapped using a swap function that is created to interchange the values of 2 variables.
