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Evgesh-ka [11]
3 years ago
12

Which of these statements about tags is false?

Computers and Technology
1 answer:
Elenna [48]3 years ago
3 0

Answer:

LOL i don't even know

Explanation:

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After a Hacker has selects her target, performed reconnaissance on the potential target's network, and probed active Internet Ad
Gnoma [55]

After a Hacker has selects her target,  the thing she scan next on the target's network to see if any are open System Ports.

<h3>How do hackers scan ports?</h3>

In port scan, hackers often send a message to all the port, once at a time. The response they tend to receive from each port will help them to known if it's being used and reveals the various weaknesses.

Security techs often conduct port scanning for a lot of network inventory and to show any possible security vulnerabilities.

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brainly.com/question/23294592

7 0
3 years ago
A cell has an unlimited number of conditions for Conditional Formatting.<br> A.true<br> B.false
Mekhanik [1.2K]
I believe the answer is false.
I Hope this helps! :)
If you don't understand plz message me
If you do plz brainlest
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7 0
3 years ago
To track what level a player is on, you can create a simple variable and a block saying change level by 1 attached to the when g
marishachu [46]

Answer:

False

Explanation:

I did it on edgnuity also i got it right

5 0
3 years ago
In this chapter, you saw an example of how to write an algorithm that determines whether a number is even or odd. Write a progra
vagabundo [1.1K]

Answer:

// Program is written in Java Programming Language

// Comments are used for explanatory purpose

// Program starts here

public class RandomOddEve {

/** Main Method */

public static void main(String[] args) {

int[] nums = new int[100]; // Declare an array of 100 integers

// Store the counts of 100 random numbers

for (int i = 1; i <= 100; i++) {

nums[(int)(Math.random() * 10)]++;

}

int odd = 0, even = 0; // declare even and odd variables to 0, respectively

// Both variables will serve a counters

// Check for odd and even numbers

for(int I = 0; I<100; I++)

{

if (nums[I]%2 == 0) {// Even number.

even++;

}

else // Odd number.

{

odd++;

}

}

//.Print Results

System.out.print("Odd number = "+odd);

System.out.print("Even number = "+even);

}

8 0
4 years ago
Read 2 more answers
It is considered good practice to save a presentation before printing it. true false
Ilya [14]
It is true because it is really a good practise to save a presentation before printing it

5 0
3 years ago
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