17. The mass of the products of a chemical reaction the mass of the reactants.

Individual iv-3 is born as a male affected with condition b but not condition

ra1l [238]

The probable genotype of the IV-3 with the perspective of autosomal inheritance will be A because he does not have condition A. Therefore both parents must be in condition A.
The probable genotype of IV-3 with the perspective of set=linked inheritance will be BbY this is because he has B condition. Therefore the mothers' genotype must be XBXb and the father's genotype must be XBY.
The probability of IV-4 having condition A is 1/36

7 0

3 years ago

List the biotic and abiotic factors in this image

BabaBlast [244]

Answer:

Biotic:

Bear
Moose
Trees
Eagle
Bird
Fish
Ducks
Otter
Ferns
Grass
Butterfly

Abiotic:

Rocks
Water
Clouds
Mountain

Explanation:

Remember that biotic factors are living organisms while abiotic factors are things that are non living organisms.

Hope this helps.

8 0

2 years ago

An animal cell lacking carbohydrates on the external surface of its plasma membrane would likely be impaired in which function?

PilotLPTM [1.2K]

An animal cell lacking carbohydrates on the external surface of its plasma membrane would likely be impaired in CELL TO CELL RECOGNITION.
Carbohydrates have diverse functions, one of their functions is that they serve as a recognition signal at the surface of cells.
Carbohydrates located on the surface of cells enable cells to recognize and communicate with one another.

4 0

3 years ago

In pea plants, long stems are dominant to short stems, purple flowers are dominant to white, and round peas are dominant to wrin

meriva

Assuming the genes are not linked nor interacting with each other, the expected number of long stemmed plants with purple flowers, producing wrinkled peas, L-P-rr, is 288.

<h3>Available data</h3>

long stems are dominant to short stems
purple flowers are dominant to white,
round peas are dominant to wrinkled

Each trait is determined by a single, different gene.

A heter0zyg0us plant is self-crossed
F1) 2,048 descendants

Let us name te alleles as follows

L ⇒ Long stem
l ⇒ Short stem
P ⇒ Purple flowers
p ⇒ white flowers
R ⇒ Round peas
r ⇒ wrinkled peas

Cross) heter0zyg0us plant is self-crossed

Parental) LlPpRr

Gametes) LPR, LPr, LpR, Lpr, lPR, lPr, lpR, lpr

Assuming that these genes are not linked nor interacting with each other, to make the calcs easier we will make crosses considering each gene separately.

Stems

Parental) Ll x Ll

F1) 1/4 LL, 2/4 Ll, 1/4 ll

3/4 long stem, 1/4 short stem

Flower color

Parental) Pp x Pp

F1) 1/4 PP, 2/4 Pp, 1/4 pp

3/4 purple flowers, 1/4 white flowers

Peas

Parental) Rr x Rr

F1) 1/4 RR, 2/4 Rr, 1/4 rr

3/4 round peas, 1/4 wrinkled peas

Now, we will get the proportion of individuals with long stems, purple flowers, producing wrinkled peas, L-P-rr

Note: The symbol - is representing either a dominant or a recessive allele.

From the crosses, we know that

3/4 are long stemmed,
3/4 have purple flowers, and
1/4 have wrinkled peas.

To get the proportion of individuals expressing all these traits together, we just need to multiply these values.

3/4 L- x 3/4 P- x 1/4 rr = 9/64 L-P-rr

Knowing that the total number of plants is 2,048 and that there are 64 possible gametes combinations from this cross, we will use the proportion 9/64 to get the number of plants with these traits.

64 ------------- 2,048 plants

9 -------------- X = (9 x 2048) / 64 = 288 plants.

We expect to find 288 long stemmed plants with purple flowers, producing wrinkled peas.

You will learn more about trihybrid crosses at

brainly.com/question/21942441

brainly.com/question/7333760

brainly.com/question/6764853

4 0

2 years ago

What’s this answer to this ?

sineoko [7]

Answer: