It would be in the 40,000,00 range
Hope this helps
Answer: The starting time is 2:27 and finishing time is 7:09.
Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.
Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.
That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes, so the time taken to cover 1 street is 3 minutes.
Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.
And his finishing time was (4:30 + 3×53 min) = 7:09.
Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as

Thus, the starting and finishing time was 2:27 and 7:09 respectively.
Exact value of x will be 8 x sin(60)
Exact value of sin 60 = √3/2
So √3/2 x 8= 8 √3/2
Can be simplified to 4 √3
Answer:
∛27 = 3
Step-by-step explanation:
A radical is simply a fractional exponent: ![a^{(\frac{m}{n})} = \sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=a%5E%7B%28%5Cfrac%7Bm%7D%7Bn%7D%29%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
Hence, ∛27 = 
Since 27 = 3³, then:
You could rewrite ∛27 as ∛(3)³.
![\sqrt[3]{3^{(3)} } = 3^{[(3)*(\frac{1}{3})]}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%5E%7B%283%29%7D%20%7D%20%3D%203%5E%7B%5B%283%29%2A%28%5Cfrac%7B1%7D%7B3%7D%29%5D%7D)
Multiplying the fractional exponents (3 × 1/3) will result in 1 (because 3 is the <u><em>multiplicative inverse</em></u> of 1/3). The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product as 1.
Therefore, ∛27 = 3.
Answer:
Thus the last row has 119 seats.
The total number of seats in 24 rows = 1476
Step-by-step explanation:
The number of seats in each row make an arithmetic series. We will use arithmetic equation to find the number of seats in last row:
An = a1+ (n-1)d
An = 4+(24-1)5
An = 4 + (23)(5)
An = 4 + 115
An = 119
Thus the last row has 119 seats.
Now to find the sum of seats we will apply the formula:
Sn = n(a1 + an)/2
Sn = 24(4+119)/2
Sn = 24(123) /2
Sn = 1476 .....
The total number of seats in 24 rows = 1476....