$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
y=a(x- h)^2+ k\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
\stackrel{\textit{zeros\qquad \qquad \qquad }}{
\begin{cases}
x=-4\implies &x+4=0\\
x=2\implies &x-2=0
\end{cases}}
\\\\\\
\stackrel{\textit{factored vertex form}}{y=a(x+4)(x-2)}\qquad (6,10)\textit{ we also know that }
\begin{cases}
x=6\\
y=10
\end{cases}
\\\\\\
10=a(6+4)(6-2)$

3 0

3 years ago

Read 2 more answers

What is the rule for the reflection? Pls help me

Luda [366]

I want to say B
This is filler to answer

6 0

3 years ago

Suppose that A and B are points on the number line.

oksian1 [2.3K]

Answer:

Suppose that A and B are points on the number line.

If AB=11 and A lies at 6, where could B be located?

If there is more than one location, separate them with commas

Step-by-step explanation:

Suppose that A and B are points on the number line.

If AB=11 and A lies at 6, where could B be located?

If there is more than one location, separate them with commas

4 0

3 years ago

2×+16=12(..........+...........)​

2×+16=12(..........+...........)