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vampirchik [111]
3 years ago
13

*URGENT* The last time she checked, Mia's pet snake was 80 inches long. Mia just measured her pet snake again and found out that

it is 30% longer. How long is the pet snake now?
Mathematics
1 answer:
Gnoma [55]3 years ago
5 0

Answer: 104

I think i'm not totally sure if this is right.

Step-by-step explanation:

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Can someone please help me?
Pavlova-9 [17]

Answer:5

Step-by-step explanation: the like moves at and angle bc u started going faster due to running

8 0
3 years ago
Read 2 more answers
NEED HELP ASAP
algol [13]

Answer:

A) car one is linear because it decreases the same amount every year.  

    car two decreases by the same ratio so it's exponential.  

B) for car one y = -6,000x + 38,000 (y is the value after x years, -6,000 is what it changes by every year, and 38,000 is the amount of year 0)

   for car two y = (44,000) (17/20)x-1 (y is the value after x years, 44,000 is the amount on year 0, and 17/20 is the ratio)

C) after 5 years car one will be 8,000

    after 5 years car two will be about 16,860

7 0
3 years ago
Simplify 9 − (−4).<br><br> −13<br> −5<br> 5<br> 13
olchik [2.2K]

Answer:

13

Step-by-step explanation:

two negatives make a positive

4 0
3 years ago
The vertices of △JKL are J(−1, 8), K(3, 5), and L(6, −9). What are the vertices of T&lt;4, −2&gt;(JKL)?
mestny [16]
J'=(3, 6); K'=(7, 3); L'=(10, -11)

This is a translation vector that shifts the figure 4 right and 2 down.  We add 4 to each x-coordinate and subtract 2 from each y-coordinate.
J'=(-1+4, 8-2) = (3, 6)
K'=(3+4, 5-2) = (7, 3)
L'=(6+4,-9-2) = (10,-11)
5 0
4 years ago
You draw two marbles from a bag containing 3 blue marbles,2 green marbles and 5 red marbles without replacement. what is the pro
lina2011 [118]
The probability of drawing a red marble then a green marble would be 1/9.
In the first draw, there is a total of 10 marbles to choose from, and choosing a red marbles' probability would be 5/10, or 1/2. However in the second draw, there are only 9 marbles to choose from since you have already taken out a marble. Choosing a green marble in the second draw's probability would be 2/9. Using the rule P(A and B) = P(A) • P(B), we can also apply it to this problem "P(choosing a red marble first and then choosing a green marble second)" = 1/2 • 2/9, which is equal to 2/18. If you simplify that, you get 1/9.
5 0
3 years ago
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