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Sergeeva-Olga [200]
3 years ago
15

X+y=8 2x-y=16 3x+z=18

Mathematics
2 answers:
Rashid [163]3 years ago
6 0
The answer is (x, y, z)=(8, 0, -6)
You have to substitute the values
x=8-y
2x-y=16
3x+z=18
Then you simplify
2(8-y)-y=16
3(8-y)+z=18
Next you substitute the value of y
y=0
-3y+z=-6
After that you solve the equation
-3x0+z=-6
Then you substitute the value of y
z=-6
Simply
x=8-0
So a possible solution will be 8.
(X, y, z)=(8, 0, -6)
Simply
8+0=8
2x8-0=16
3x8+(-6)=18
The ordered triple is the solution
8=8
16=16
16=18
(x, y, z) = (8, 0, -6)
asambeis [7]3 years ago
3 0

Answer:

x+y-8=0

Step-by-step explanation:

It makes the most sense

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B. 8+(-10)


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Help! You can look at the picture please
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Answer:

\frac{3x}{3 - 2x}

Step-by-step explanation:

Here,

f(x) = y

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x =  \frac{3y}{2y + 3}

now to solve for y we get

y =  \frac{3x}{3 - 2x}

now we put f inverse x instead of y

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4 0
4 years ago
Read 2 more answers
Which line has an equation of y=-5x+4 in slope-intercept form?
Lady bird [3.3K]
<span>D: a line passing through the points (2, –6) and (4, –16)</span>
4 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
4 years ago
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