A regular quadrilateral prism has 12 edges. It is given perimeter of the base 32 cm. Length of each edge of base will be 32÷4=8 cm. The 4 edges at the top will also have the same number of edges that is 4 with measure 8cm each.
Given: The height of the prism is 2 times greater than the length of the base edge.Height of prism = 2(8)= 16cm. Number of edges with measure 16 cm is 4.
Sum of all the 12 edges= 8+8+8+8+16+16+16+16+8+8+8+8=128 cm.
It’s actually a. Multiply by the square root of 2
You can verify using the Pythagorean Theorem.
Step-by-step explanation:
area of a triangle =½bh
35=½×(3x-2)(x+3)
70=3x²+9x-2x-6
70=3x²+7x-6
3x²+7x-64=0
continue from there
I would appreciate if my answer is chosen as a brainliest
Answer:
2
Step-by-step explanation:
The remaining two can be given in either order:
YXZ
YZX
