Answer:
D. 63
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse<u>
</u>
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Leg <em>a</em> = 9
Leg <em>b</em> = <em>b</em>
Leg <em>c</em> = 12
<u>Step 2: Solve for </u><em><u>b</u></em>
- Substitute in variables [Pythagorean Theorem]: 9² + b² = 12²
- [Subtraction Property of Equality] Isolate <em>b</em> term: b² = 12² - 9²
- Evaluate exponents: b² = 144 - 81
- Subtract: b² = 63
- [Equality Property] Square root both sides: b = √63
Answer:
a) P{W>0} = 0.5
b) P{W<0} = 0.5
c) E[W] = 0
Step-by-step explanation:
Solution:
a) P(W > 0) is 0.5 because there is a 0.5 chance the player will win on their first gamble and stop with a net profit.
b) P(W = 0) is 0.25 because there is a 0.5 chance the player will lose on their first gamble, then also a 0.5 chance they will win on their second gamble and stop with a profit of 0.
All other combinations of gambles result in a net loss, so P(W < 0) = 1−P(W > 0)−P(W = 0)
c) The expected value can be obtained by summing the products of each profit and the probability of that profit. In this case, you have 1∗0.5+0∗0.25+(−1)∗0.125+(−2)∗0.0625, etc. So E(W) is the sum to infinity:
= (1 - n) / 2^( n + 1 )
= 0
Answer:
The answer to your question is letter C
Step-by-step explanation:
Data
hamburgers = h
fries = f
soda = s
Student 1 4h + 4f + 1s = 21
Student 2 1h + 1f + 1s = 5
Student 3 1h + 1f = 5
From the data of students 2 and 3 we can conclude that the system will not have a solution because is not possible that one student has charged 3 items for the same cost of student 3 that bought only 2 items.
Hello,
3ln(3) - ln(9)=ln(3^3)-ln(9)=ln(3^3/9)=ln(3)=1,0986122886681....
