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sladkih [1.3K]
3 years ago
9

How do I solve part b?

Mathematics
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

x \approx 1.4

Step-by-step explanation:

This problem gives one the following equation to model the graph of a line: (y=x^2-2). The problem asks one to find the value of (x) when (y=0). Rather than using the graph, an easier way to solve this problem is to substitute (0) in for the value of (y) and then solve for (x) using inverse operations.

y=x^2-2\\

Substitute,

0=x^2-2

Inverse operations,

0=x^2-2\\\\2=x^2\\\\\sqrt{2}=x

Round:

x \approx 1.4

As one can see on the graph, this result is very close to the value at which the graph intersects the (x) axis. Thus, one can conclude that (x) does indeed approximately equal (1.4)

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jake carries a green a yellow and a black guitar pic in his pocket. he randomly chooses a guitar pic from his pocket before ever
SIZIF [17.4K]
B = Black
G = Green
Y = Yellow
The total number of ways that he can pick a pic are 3 * 3 * 3 = 27 ways
If he picks Black for the first pic The number of successful ways that he picks two in a row are
B B G
B B Y
B G G
B Y Y  Total 4 ways.
If he picks Green first the number of ways are
G G B
G G Y
G B B
G Y Y Total 4 ways
If he picks Yellow first then the number of ways are
Y Y B
Y Y G
Y B B
Y G G And again there are 4 ways

In all we have 12 successes
There are 12/27 chances of picking 2 pics in a row that are the same color.
4/9 <<<< answer

There must be some way to represent this using combinations, but I'm not sure what it is. However this method works.


 

4 0
4 years ago
The sequence 2, 3, 5, 6, 7, 10, 11, $\ldots$ contains all the positive integers from least to greatest that are neither squares
sergeinik [125]
The 400th term is 425.

There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are \lfloor\sqrt[6]{427}\rfloor=2 numbers that are both squares and cubes. Consequently, the 400th term will be 427-2 = 425.
7 0
3 years ago
If the midpoints of the sides of ∆EFG shown below were connected with line segments, what would be the perimeter of the resultin
masya89 [10]

Answer:

17.5

Step-by-step explanation:

I beleive since we are connecting midpoints you divide each side by 2 and add them all up to get the perimeter of the smaller triangle made with the ratio of 1:2

6 0
3 years ago
Please help!!!! and when you answer please explain how you got it so in the future I can understand it
UNO [17]

Answer:

It does

Step-by-step explanation:

This is because the line has points in which time and distance are connected (Ex. 100 and 2)

Hope this helps! :)

7 0
3 years ago
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g100num [7]
The curved surface area is equal to about 354.53
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3 years ago
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