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2 years ago

How do I solve part b?

Mathematics

1 answer:

Minchanka [31]2 years ago

6 0

Answer:

$x \approx 1.4$

Step-by-step explanation:

This problem gives one the following equation to model the graph of a line: ( $y=x^2-2$ ). The problem asks one to find the value of (x) when (y=0). Rather than using the graph, an easier way to solve this problem is to substitute (0) in for the value of (y) and then solve for (x) using inverse operations.

$y=x^2-2\\$

Substitute,

$0=x^2-2$

Inverse operations,

$0=x^2-2\\\\2=x^2\\\\\sqrt{2}=x$

Round:

$x \approx 1.4$

As one can see on the graph, this result is very close to the value at which the graph intersects the (x) axis. Thus, one can conclude that (x) does indeed approximately equal (1.4)

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If z varies directly as x and z=30 when x=8 find z when x=4

dangina [55]

Z=kx, 30=8k, so k=30/8=15/4 and z=15x/4, so when x=4, z=15.

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3 years ago

What is the volume of this triangular prism?

Liula [17]

Answer:

5676.16 cm^3

Step-by-step explanation:

The volume of any prism is given by the formula ...

V = Bh

where B is the area of one of the parallel bases and h is the perpendicular distance between them. Here, the base is a triangle, so its area will be ...

B = 1/2·bh

where the b and h in this formula are the base and height of the triangle, 28 cm and 22.4 cm.

Then the volume is ...

V = (1/2·(28 cm)(22.4 cm))·(18.1 cm) = 5676.16 cm^3

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You will note that this is half the product of the three dimensions, so is half the volume of a cuboid with those dimensions. Perhaps you can see that if you took another such prism and placed the faces having the largest area against each other, you would have a cuboid of the dimensions shown.

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3 years ago

Read 2 more answers

Plz help me I really need help

Zepler [3.9K]

Answer:

5/9

Step-by-step explanation:

let other fraction be x

x+1/3=8/9

x=8/9-1/3

x=(8-1*3)/9

x=(8-3)/9

x=5/9

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3 years ago

Which of the following sentences is true? 30.744 is greater than 30.844. 9.542 is greater than 9.532. 182.348 is less than 182.3

Arturiano [62]

Answer:

the first sentance is wrong, the second one is right, the third one is right and the last one is wrong

Step-by-step explanation:

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3 years ago

Alex is a writer who writes poems and short stories. For an upcoming writer's workshop Alex wants to write some new works. He ne

pashok25 [27]

Answer:

The maximum number of works that he can write while staying in his time budget is 24.

21 poems and 3 short stories

Step-by-step explanation:

In order to solve this problem we must first determine what our variables are. In this case it's the number of poems and short stories he can write.

p = # of poems

s = # of short stories

Next, we must build our objective function which will represent the total number of works he can write.

N=p+s

where N is the number of works.

Next, we must write the constrains based on the information provided by the problem.

The problem tells us that it takes him 30 hours to write a poem and 70 hours to write a short story and that he has 840 hours available to write them, so that constrain will be the following:

$30p+70s \leq 840$

it also tells us that he wants to write at least 4 poems and 3 short stories so there we have our other two constrains.

$p \geq 4$

$s \geq 3$

once we got our constrains we can go ahead and graph them to see how they will behave. (See attached picture)

In the graph p is the horizontal axis and s is the vertical axis.

On the graph we can see a polygon that is formed by the restriction. The vertices of the polygon will represent the optimal conditions for this linear programming problem. There are three optimal solutions there, so we need to test them to see which will return the greatest number of works he can write while keeping the given conditions.

Option 1:

4 poems and 3 short stories

N=4+3

N= 7 works

Option 2:

4 poems and 10 short stories

N=4+10

N=14 works

Option 3:

21 poems and 3 short stories

N=21+3

N=24 works

So the optimal solution will be given by option 3 with 21 poems and 3 short stories.

5 0

2 years ago