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3 years ago

Collect like terms to simply the expression

Mathematics

2 answers:

viva [34]3 years ago

6 0

Answer:

1=0 2

Step-by-step explanation:

Ipatiy [6.2K]3 years ago

5 0

1= 0 2 is your answer heheehe

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HELP PLEASE DUE IN 4 MINUTES

iragen [17]

Answer:

Mode: 11

Median: 11

Step-by-step explanation:

mode is number that shows up the most

Arrange numbers in order :

7 8 9 10 11 11 12 13 18

number physically in the middle is median

5 0

3 years ago

Read 2 more answers

Answer correctly plz

Ne4ueva [31]

Answer:

1/3

Step-by-step explanation:

Use the Up/to left or right rule to help you

Find a start point (or the one the gave you (3,2)) and then follow the line to the next point that crosses exactly over where to points cross (where poth x and y would be whole numbers) count how many times the point moved up, then how many time it moved left. Put the first over the second in fraction form and there is your slope.

8 0

2 years ago

Read 2 more answers

Long division.... <br> (M^2-7m-11) ÷ (m-8)<br><br> We are so lost....

sergejj [24]

Well, (m^2-7m-11) ÷ (m-8) = m+1 with a remainder of -3

6 0

3 years ago

If the ratio of the length of segment AC to the length of segment CB is 3:1, what is the y-coordinate of point C?

Yuki888 [10]

Answer:

The coordinates of point C are (8,8.5)

Step-by-step explanation:

The picture of the question in the attached figure

Let

$(C_x,C_y)$ ----> coordinates of point C

we have that

The horizontal distance AB is equal to

$AB_x=10-2=8\ units$

The vertical distance AB is equal to

$AB_y=10-4=6\ units$

Find the horizontal coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

$\frac{AC_x}{CB_x}=\frac{3}{1}$

$AC_x=3CB_x$ ----> equation A

$AC_x+CB_x=8$ ----> equation B

substitute equation A in equation B

$3CB_x+CB_x=8$

$4CB_x=8\\CB_x=2$

$AC_x=3(2)=6$

The x-coordinate of point C is equal to the x-coordinate of point A plus the horizontal distance between the point A and point C

$C_x=A_x+AC_x=2+6=8$

Find the vertical coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

$\frac{AC_y}{CB_y}=\frac{3}{1}$

$AC_y=3CB_y$ ----> equation A

$AC_y+CB_y=6$ ----> equation B

substitute equation A in equation B

$3CB_y+CB_y=6$

$4CB_y=6\\CB_y=1.5$

$AC_y=3(1.5)=4.5$

The y-coordinate of point C is equal to the y-coordinate of point A plus the vertical distance between the point A and point C

$C_y=A_y+AC_y=4+4.5=8.5$

therefore

The coordinates of point C are (8,8.5)

5 0

3 years ago

How do I solve

Maslowich

$Use:\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\------------------------\\\\\left(16n^4\right)^{\frac{5}{4}}=16^\frac{5}{4}\left(n^4\right)^\frac{5}{4}=16^{1\frac{1}{4}}n^{4\cdot\frac{5}{4}}=16^{1+\frac{1}{4}}n^5=16^1\cdot16^\frac{1}{4}\cdot n^5\\\\=16\cdot\sqrt[4]{16}\cdot n^5=16\cdot2\cdot n^5=\boxed{32n^5}\\\\\sqrt[4]{16}=2\ because\ 2^4=16\\\\\text{Answer}\ \boxed{\left(16n^4\right)^\frac{5}{4}=32n^5}$

4 0

3 years ago