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3 years ago

Can someone help me please ASAP

Mathematics

1 answer:

Mamont248 [21]3 years ago

6 0

Answer

25f + 100c <span>≤ 700

hope it helps</span>

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Step 2: Radii OK and NL are perpendicular to OM because of the radius-tangent theorem. By definition of perpendicular, angles KO

solong [7]

Answer:

Angle Angle Angle (AAA) property

Step-by-step explanation:

A right angled triangle is a triangle that has one of its angles to equal $90^{0}$ . It could be in the form of an isosceles triangle or an acute angled triangle.

The given question compares the congruence properties of two triangles, KOM and LNM.

Thus,

<KOM = <LNM (right angle theorem)

<LMN = <KMO (common angles to both triangles)

⇒ <OKM = <NLM (property of a triangle i.e sum of angle in a triangle is $180^{0}$ )

ΔKOM = ΔLNM (congruence property)

Therefore, by angle angle angle (AAA) congruence property, the two triangles are similar.

7 0

3 years ago

Simplify 3x³(x+2)+2x(x²+3x)

max2010maxim [7]

Answer:

${3x}^{4} + {8x}^{3} + {6x}^{2}$

Step-by-step explanation:

${3x}^{3} (x + 2) + 2x( {x}^{2} + 3x)$

${3x}^{4} + {6x}^{3} + {2x}^{3} + {6x}^{2}$

${3x}^{4} + {8x}^{3} + {6x}^{2}$

<h3>Hope it is helpful...</h3>

8 0

3 years ago

The table shows the numbers of seeds the owners of pumpkin patch farms received from different seed suppliers. Each of the pumpk

vaieri [72.5K]

Answer:I’m trying to find it too

Step-by-step explanation:I don’t know what it is but I’m sure it’s 12-90

5 0

2 years ago

Need help real quick!!!

ExtremeBDS [4]

Answer:

what help you needed. ??

5 0

2 years ago

Find the standard deviation of 21, 31, 26, 24, 28, 26

Vesnalui [34]

Given the dataset

$x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}$

We start by computing the average:

$\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26$

We compute the difference bewteen each element and the average:

$x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}$

We square those differences:

$(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}$

And take the average of those squared differences: we sum them

$\displaystyle \sum_{i=1}^n (x-\overline{x})^2=36+25+4+4+0+0=69$

And we divide by the number of elements:

$\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5$

Finally, we take the square root of this quantity and we have the standard deviation:

$\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39$

8 0

3 years ago