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3 years ago

Pls help me with 5 and 6 PLEASE ASAP (try showing work if u can) thank you!!!

Mathematics

1 answer:

Butoxors [25]3 years ago

8 0

5. B. -$143.23 because they lost that amount. You would do $225.98 minus 62.75 and just turn it negative

6. D. 13/20 miles west because you had more to go west so either B or D and then you know that you couldn't have a number before the fraction since 3/5 was bigger then 1/4.

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A golfer’s score of 3 under par is -3 on a number line. What would a golfer’s score of 3 over par be?

tankabanditka [31]

If 3 under is -3 than 3 over would be positive 3

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4 years ago

A type of long-range radio transmits data across the Atlantic Ocean. The number of errors in the transmission during any given a

Marianna [84]

Answer:

32.33% probability of having at least 3 erros in an hour.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The mean number of errors is 2 per hour.

This means that $\mu = 2$

(a) What is the probability of having at least 3 errors in an hour?

Either you have 2 or less errors in an hour, or we have at least 3 errors. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 2) + P(X \geq 3) = 1$

We want $P(X \geq 3)$

$P(X \geq 3) = 1 - P(X \leq 2)$

In which

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}*(2)^{0}}{(0)!} = 0.1353$

$P(X = 1) = \frac{e^{-2}*(2)^{1}}{(1)!} = 0.2707$

$P(X = 2) = \frac{e^{-2}*(2)^{2}}{(2)!} = 0.2707$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.1353 + 0.2707 + 0.2707 = 0.6767$

$P(X \geq 3) = 1 - P(X \leq 2) = 1 - 0.6767 = 0.3233$

32.33% probability of having at least 3 erros in an hour.

6 0

3 years ago

Select the correct answer from each drop-down menu. The table below represents the function f, and the following graph represent

Lorico [155]

<h3>Answers:</h3>

The functions f and g have <u>same axis of symmetry</u>

The y intercept of f is <u>greater than</u> the y intercept of g.

Over the interval [-6,-3], the average rate of change of f is <u>less than</u> the average rate of change of g.

===========================================

Explanation:

Check out the diagram below.

Using the table, plot each (x,y) point onto the same xy grid the blue parabola is graphed on. This way we can compare the two graphs. I'll show these points in red. The red parabola passing through them represents all of f(x) assuming it is continuous.

When we have f(x) and g(x) plotted together, we see that they have the same axis of symmetry. Points D = (-3,-10) and K = (-3,7) have the same x coordinate. The axis of symmetry for each is x = -3.

-------------

Furthermore, the graph shows that the y intercept of f is above the y intercept of g. Look where the graphs cross the y axis. So The y intercept of f is greater than the y intercept of g

We could note that from the table, the y intercept of f is (0,8) as the y intercept always happens when x = 0.

-------------

Last part is the average rate of change (AROC)

AROC is the same as the slope of the line through the endpoints mentioned. The interval [-6, -3] means we go from x = -6 to x = -3. Those x values determine the endpoints.

For f(x), this means we find the slope of the line through (-6,8) and (-3,-10). Use the slope formula to get

m = (y2-y1)/(x2-x1)

m = (-10-8)/(-3-(-6))

m = (-10-8)/(-3+6)

m = -18/3

m = -6 ... negative slope goes downhill as we move from left to right

The AROC for f, on the mentioned interval, is -6

The AROC for g is done in a similar manner. We use the two points J = (-6,-2) and L = (-3,7) as the diagram shows. The slope of line JL is

m = (y2-y1)/(x2-x1)

m = (7-(-2))/(-3-(-6))

m = (7+2)/(-3+6)

m = 9/3

m = 3 ... positive slope goes uphill as we move from left to right

We get a different AROC here. More specifically, this is a larger AROC compared to what we got for f. So the AROC for f is smaller than the AROC for g.