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kvv77 [185]
3 years ago
6

What is the value of x in the equation 8x – 2y = 48, when y = 4?

Mathematics
1 answer:
luda_lava [24]3 years ago
8 0

Answer:

7

Step-by-step explanation:

8x-2y=48, replace y with 4, 8x-2(4)=48, multiply, 8x-8=48, add 8 to both sides to remove the -8, 8x=56 and finally divide by 8 to remove 8 from x, x=7.

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Answer:

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And 99% confidence interval estimate of the true weight is:

3.150±\frac{4.604*0.1}{\sqrt{5} }≈3.150±0.206

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