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Anettt [7]
3 years ago
8

A student estimated a mass for by 325g, but upon carefully mesuring it, found the actual mass to be 342g. What is the percent er

ror?
Mathematics
1 answer:
vlada-n [284]3 years ago
7 0

Answer:

5.2307 %

Step-by-step explanation:

(acutal mass- estimated mass) / ( estimated mass)

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There is 3/4 of a cake there are 8 friends how much cake does each friend get
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Each student will get 3/32 of the cake :)
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3 years ago
What is the definition of perfect cube and can you give an example
PilotLPTM [1.2K]
A perfect cube is a natural number in the form
{a}^{3}  = a \times a \times a
therefore
{1}^{3}  = 1 \\  {2}^{3}  = 8 \\  {3}^{3}  = 27 \\  {4}^{3}  = 64 \\  {5}^{3 }  = 125 \\ . \\ . \\ .\\ .
and also you can define it as any natural number who's third root is also a natural number for examble
\sqrt[3]{1000}  = 10
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6 0
2 years ago
Insert parentheses into the expresstion 15+3-6×4 to make it equal 48​
Nat2105 [25]

Answer:

(15+(3-6))x4

Step-by-step explanation:

1. 3-6 = -3

2. 15+-3 = 12

3. 12x4 = 48

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2 years ago
The four diagonals of a cube are drawn to create 6 square pyramids with the same base and height. The volume of the cube is (b)(
marshall27 [118]

Answer: A

Step-by-step explanation:

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Read 2 more answers
Find the distance from the point (9, –2) to the line y = 3∕2x + 4. Choices are in the attachment...
zimovet [89]
<h3>Answer: Choice B)  \sqrt{117} \text{ units}</h3>

===================================================

Work Shown:

y = (3/2)x + 4

2y = 3x + 8 .... multiply both sides by 2

0 = 3x + 8 - 2y

3x-2y+8 = 0

The original equation transforms to 3x-2y+8 = 0. It is in the form Ax+By+C = 0. We see that A = 3, B = -2, C = 8. This form is very useful to help find the distance from a point to this line.

The formula we will use is

d = \frac{|A*p+B*q+C|}{\sqrt{A^2+B^2}}\\\\

where A,B,C were the values mentioned earlier. The p,q are the x and y coordinates of the point given. So p = 9 and q = -2

Plugging all that in gives...

d = \frac{|A*p+B*q+C|}{\sqrt{A^2+B^2}}\\\\d = \frac{|3*9+(-2)*(-2)+8|}{\sqrt{3^2+(-2)^2}}\\\\d = \frac{|27+4+8|}{\sqrt{9+4}}\\\\d = \frac{|39|}{\sqrt{13}}\\\\d = \frac{39}{\sqrt{13}}\\\\d = \frac{39\sqrt{13}}{\sqrt{13}\sqrt{13}} \ \text{ rationalizing denominator}\\\\d = \frac{39\sqrt{13}}{13}\\\\d = 3\sqrt{13}\\\\d = \sqrt{9}*\sqrt{13}\\\\d = \sqrt{9*13}\\\\d = \sqrt{117}\\\\

6 0
3 years ago
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