Answer:
C. The enzyme with mutation 1 has decreased affinity for pyridoxal phosphate, whereas the enzyme with mutation 2 has lost the ability to bind to the substrates.
Explanation:
A coenzyme is an organic cofactor that binds with an enzyme in order to initiate or aid the function of the enzyme. A coenzyme binds to the active site of the enzyme (where the reaction occurs), thereby triggering its activation by modifying protein structure during the reaction. Some examples of coenzymes include Coenzyme A and Adenosine triphosphate (ATP). Pyridoxal phosphate is a coenzyme (it is the active form of vitamin B6) that is required for the function of cystathionase. Moreover, cystathionase is an enzyme that enables cells the synthesis of cysteine from methionine (transsulfuration pathway). The binding of pyridoxal phosphate to the enzyme increases the binding affinity of the enzyme for the substrate, thereby influencing its activity. In this case, it is expected that mutation 1 reduces the binding affinity of the enzyme to the cofactor, and thereby the cofactor is required at a higher concentration to restore normal enzyme activity.
Matter that is not used by consumers in the food chain become "detritus". Detritus, meaning debris or waste, are materials that are missed or uneaten by consumers. Because they do not participate in higher trophic levels, these materials are left to decompose. Detritus is often considered the "missing mass" when measuring the total mass in the food chain.
We can define the solubility as the maximum amount of solute (which may be a solid, liquid or gas) that is dissolved in a solvent ( which may be a solid, liquid or gas).
The solubility of Ammonium chloride (NH₄Cl) at 50°C is 50 grams, because t<span>he </span>solubility of NH₄CL<span> is 50g /100g of water at </span>50°<span> C.</span>
Answer:
30% Thymine
Explanation:
If 30% of Adenine is present, it would be reasonable to assume that 30% of Thymine will be present, as the ratio between the two complementary nitrogenous bases will be roughly equal.
Therefore, that leaves us with 40% between Cytosine and Guanine. Since the ratio between them would be equal, it gives us 20% of Cytosine and 20% of Guanine.
<u>Therefore:</u>
30% of A + 30% of T + 20% of C + 20% of G = 100% DNA
Feral rock pigeons were screened for neutralizing antibodies to West Nile virus during late winter/spring and summer of 2002 and 2003. Additionally, virus isolation from serum was attempted from 269 birds collected during peak transmission
