Question

Please help me Algebra 1

Answer 1

Answer:

a.  $\sqrt{x^n}$ = $x^\frac{n}{2}$

b. $\sqrt{x^n} = x^\frac{(n-1)}{2}\sqrt{x}$

Step-by-step explanation:

a) When n is even, then it is divisible by 2. Because of this, you can write:

• $\sqrt{x^n} = (x^n)^\frac{1}{2}$

• $\sqrt{x^n} = x^\frac{n}{2}$

b) When n is odd, then n - 1 is even. This would make it divisible by 2, and there would be a remainder of 1, so we can write:

• $\sqrt{x^n} = (x^n^-^1^+^1) ^\frac{1}{2}$

• $\sqrt{x^n} = (x^n^-^1$ × $x)^\frac{1}{2}$

• $\sqrt{x^n} = x^\frac{(n-1)}{2}$ × $x^\frac{1}{2}$

• $\sqrt{x^n} = x^\frac{(n-1)}{2}\sqrt{x}$

Answer 2

I don’t know but I think it is b