Please help........................

Mathematics

1 answer:

ivanzaharov [21]3 years ago

6 0

The volume of a sphere is 4/3 * pi * r³ so substitute the values in

4/3 * pi * 2³

4/3 * pi * 8

32/3 * pi

The volume is either 32/3pi units³ or 33.49 units³ (they're the same value)

I hope this helps!

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Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11

Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .

Hope this wasn't too confusing! I'll answer any questions.

8 0

3 years ago

Read 2 more answers

What is the value of k, so that 3x²+7x+6-k=0 has one root equal to zero? <br>

djverab [1.8K]

k = 13 is the value of k in quartic equation.

What does the term "quartic equation" mean?

An equation of the fourth degree, often known as a quartic equation, is one that reduces a quartic polynomial to zero. in which a 0. A quartic function's derivative is a cubic function.

Let α = 7x

β = 6x

α + β = 7x + 6x = k/3 ............1

13x = k/3

αβ = 7x × 6x = 14/3

42x² = 14/3

x² = 14/3 × 42

x² = 1/9

x = 1/3

now putting value of x in 1

7/3 + 6/3 = k/3

1/3( 7 + 6 )= k/3