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3 years ago

5log5 (17)What the steps to this problem because I don’t understand

Mathematics

2 answers:

dedylja [7]3 years ago

6 0

Answer:

8.80

Step-by-step explanation:

u can use a calculator

SIZIF [17.4K]3 years ago

4 0

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The length of a rectangle is 1 more yd than twice the width, and the area of the rectangle is 66 yd squared. Find the dimensions

Salsk061 [2.6K]

Width = 5.5yd

Length = 12yd

Explanation:

Area of rectangle = $66yd^{2}$

Let width of the rectangle = b ,

So, length = 2b+1

Area of rectangle = (length X width) - eqn 1

Putting the value of length and width in above equation 1,

$66yd^{2} = (2b+1) X b\\66yd^{2} = 2b^{2} + b\\2b^{2} +b-66 = 0\\$

On solving the equation we get,

b = 5.5yd

So, width (b) = 5.5yd

and length = 2(5.5) + 1

l = 12yd

Hence,

Width = 5.5yd

Length = 12yd

6 0

3 years ago

Round to the nearest tenth.

laila [671]

Answer:

8.2 units

Step-by-step explanation:

Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC

Recall the Law of Cosines

$a^2=b^2+c^2-2bc\cdot cos(A)$

Identify angles and sides

$m\angle A=23^\circ\\a=BC=?\\b=AC=14\\c=AB=6$

Solve for side "a"

$a^2=b^2+c^2-2bc\cdot cos(A)\\\\a^2=14^2+6^2-2(14)(6)\cdot cos(23^\circ)\\\\a^2=196+36-168cos(23^\circ)\\\\a^2=222-168cos(23^\circ)\\\\a=\sqrt{222-168cos(23^\circ)}\\ \\a\approx8.2$

Therefore, the length of line segment BC is about 8.2 units

8 0

2 years ago

What is the area of the shaded segment?

Whitepunk [10]

Answer:

$6\pi-9\sqrt{3$

Step-by-step explanation:

The area of a pie-slice shape can be found with the equation $A=\pi nr^2/360$ where n is the angle of the shape and r is the radius of the circle. In this case, n=60 and r=6. Therefore, the total area of the pie-slice is $\pi (60)(6^2)/360=6 \pi$

Next, the triangle that makes up the unshaded part of the segment is an equilateral triangle because the angle is 60. The area of an equilateral triangle is $\sqrt{3}r^2/4$ where r is the length of one of its side (in this case, r=6). Plugging that in, we get an area of $9 \sqrt{3}$