Answer:
Zeros are x = −2, −3 .
Step-by-step explanation:
Given : f(x) = x² + 5x + 6.
To find : What are the zeroes of f(x).
Solution : We have given that
f(x) = x² + 5x + 6.
To find the zeros of the function we need to set f(x) = 0.
x² + 5x + 6 = 0.
On factoring
x² + 3x +2x + 6 = 0.
Taking common x from first two term and 2 from last two terms
x ( x + 3) +2 ( x +3) = 0.
On grouping
(x + 3) (x + 2) = 0
Now, x + 3 = 0 and x + 2 = 0
x = -3 and x = -2
Therefore, Zeros are x = −2, −3 .
2 and the 4 needs to add subtract too much
Answer:
y=4
Step-by-step explanation:
90 - 66 = 24
therefore, 8y-8 = 24
8y = 32
divide both sides by 8
y = 4
To do this, you have to plug each x value into the rule.
1.y = 15 - 3×2
y = 15 - 6
y = 9
So the first y value would be 9.
2.y = 15 - 3×3
y = 15 - 9
y = 6
3. y = 15 - 3×4
y = 15-12
y = 3
4. y = 15 - 3×5
y = 15-15
y = 0
Hope this helps!
