Answer:
34°
Step-by-step explanation:
1. First, let's find the measure of ∠1 because since r || s, that means ∠1 = ∠7 because they're both alternate exterior angles. Alternate exterior angles are congruent.
2. (Solving for ∠1)
3. Now, since we know ∠1 = ∠7, ∠7 = 34°.
Answer:
Step-by-step explanation:
b
<span>Answer: a) Greater than or equal to 38 feet
b)Since there is no restriction on the perimeter there exists many possible values for the length of the deck.
Explanation: Given that the width of the deck is 29 ft.
and the perimeter of the deck is at least 134 ft.
134 = 2(length + width)
134 = (2 x length) + (2 x 29)
134 = (2 x length) + 58
2 x length = 134 - 58
2 x length = 76
length = 76 / 2
length = 38 ft
Thus, the inequality will be:
a)Length ≥ 38 ft
b)since there is no restriction on the perimeter there exists many possible values for length of deck.</span>
A)
It looks like the [irregular] hexagon has 3 rectangles and 2 triangles within it.
So let's exclude the triangular corners on bottom left and top right for now.
First we have a large rectangle covering most of the upper left of the polygon. 20 ft × 7 ft = 140 sq.ft.
Now we have a rectangle on the bottom right. The width is 11 ft, so take the 7 away from that, 4 ft. × 14 ft. on bottom. 4 ft × 14 ft = 56 sq.ft.
The last small rectangle fits on the right between the 2 other rectangles. It is 24-20 on top/bottom × 7-6 right/left. 4 ft × 1 ft = 4 sq.ft.
Now for the triangles: bottom left is 11-7 × 24-14 = 4 ft × 10 ft. 1/2bh = 1/2×10×4 = 20 sq.ft.
Top right is 24-20 × 11-5 = 4 ft × 6 ft. 1/2bh = 1/2×4×6 = 12 sq.ft.
B)
Add them all together for the total area (A):
A = 140 + 56 + 4 + 20 + 12 = 140+60+32
= 232 sq.ft.
Hope that explains it well enough! ;)
