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3 years ago

Answer correctly for brainliest

Mathematics

2 answers:

Margaret [11]3 years ago

5 0

Answer:

Step-by-step explanation:

SSSSS [86.1K]3 years ago

4 0

Answer:

1 / 1 or 1

Step-by-step explanation:

(y2 - y1) / (x2 - x1)

(4 - (-1)) / (1 - (-4))

5 / 5 = 1 / 1 = 1

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What is the IQR of: 45, 32, 62, 26, 22, 29

madreJ [45]

Answer:

The first quartile is 26.

The third quartile is 45

The median is 30.5

The interquartile range is 19.

Hope that helped :)

Step-by-step explanation:

7 0

3 years ago

The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.What is

Lesechka [4]

Answer:

a) The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

Step-by-step explanation:

Given : The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.

To find : What is the probability that

(a) the total gross sales over the next 2 weeks exceeds $5000;

(b) weekly sales exceed $2000 in at least 2 of the next 3 weeks? What independence assumptions have you made?

Solution :

Let $X_1$ and $X_2$ denote the sales during week 1 and 2 respectively.

a) Let $X=X_1+X_2$

Assuming that $X_1$ and $X_2$ follows same distribution with same mean and deviation.

$E(X)=E(X_1+X_2)=E(X_1)+E(X_2)$

$E(X)=2\mu = 2(220)=4400$

$\sigma_X=\sqrt{var(X_1+X_2)}$

$\sigma_X=\sqrt{2\sigma^2}$

$\sigma_X=\sqrt{2}\sigma$

$\sigma_X=230\sqrt{2}$

So, $X\sim N(4400,230\sqrt{2})$

$P(X>5000)=1-P(X\leq5000)$

$P(X>5000)=1-P(Z\leq\frac{5000-4400}{230\sqrt{2}})$

$P(X>5000)=1-P(Z\leq1.844)$

$P(X>5000)=1-0.967$

$P(X>5000)=0.0321$

The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The probability that sales exceed teh 2000 and amount in at least 2 and 3 next week.

We use binomial distribution with n=3.

$P(X>2000)=1-P(X\leq2000)$

$P(X>2000)=1-P(Z\leq\frac{2000-2200}{230})$

$P(X>2000)=1-P(Z\leq-0.87)$

$P(X>2000)=1-0.1922$

$P(X>2000)=0.808$

Let Y be the number of weeks in which sales exceed 2000.

Now, $P(Y\geq 2)$

So, $P(Y\geq 2)=P(Y=2)+P(Y=3)$

$P(Y\geq 2)=^3C_2(0.8077)^2\cdot (1-0.8077)+^3C_3(0.8077)^3$

$P(Y\geq 2)=0.37635+0.52692$

$P(Y\geq 2)=0.90327$

The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

3 0

3 years ago

Find the x and y intercepts 5x -2y =10

vovangra [49]

Answer:

x-int: (2, 0)
y-int: (0, -5)

To find the x-intercept, substitute in 0 for y.

To find the y-intercept, substitute in 0 for x.

Hope this helps and hava great day!!

3 0

3 years ago

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Hi! I have been using this for a while and I went to a math question and 2 people said that the answer is 12. Here is the questi

Fofino [41]

Answer:

Cool. Thanks!

Step-by-step explanation:

8 0

3 years ago

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Which is the greatest to least, 12 3/4, 12 3/5 and 12.7

Ne4ueva [31]

Answer:

12 3/4, 12.7, 12/5

Step-by-step explanation:

12 3/4 = 12.75

12 3/5 = 12.6

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3 years ago

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