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Marta_Voda [28]
3 years ago
13

I NEED HELP PLEASE!!!

Mathematics
1 answer:
Triss [41]3 years ago
6 0

Answer:

C (-13,-2)

Step-by-step explanation:

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Simplify the following <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Cfrac%7B1%7D%7Bx%7D%20%20%2B%201%20%7D%20%7B%20%5Cfrac%2
Anon25 [30]
Good evening, Riley!

Used properties:

\star~\boxed{\mathsf{a = \dfrac{ax}{x}, \ \ x\neq 0}}\\ \\ \\ \star~\boxed{\mathsf{\dfrac{\frac{a}{b}}{\frac{c}{d}} = \dfrac{ad}{bc}}}

Now, note that:

\mathsf{1 = \dfrac{x}{x},\ x\neq 0}

So:

\mathsf{\dfrac{\frac 1 x + \frac x x }{\frac 1 x} = \dfrac{\frac{x+1}{x}}{\frac 1 x}}=} \mathsf{\dfrac{x}{1}\dfrac{x+1}{x} = \boxed{x + 1}}
8 0
3 years ago
The map below shows the path that Jin walked this morning. According to his pedometer, the total distance of this path was 2.3 k
max2010maxim [7]

Answer:

5 centimetres = 1 kilometre

Step-by-step explanation:

First add up the distances measured on the map.

1.1+4.8+2.2+3.4=11.5 cm

Based on this, since the number of cm is greater than the number of km, we can figure out that each cm should not be multiplied to get the km, so we can eliminate the first two answers.

Next write an equation to represent finding the scale

x=scale

11.5=2.3x

Now solve for the scale

11.5/2.3=2.3x/2.3

5=x

Therefore the scale is 5 centimetres = 1 kilometre

6 0
3 years ago
Please help I have a D in this class.
maxonik [38]

Answer:

the value of x in terms of b is bx=-13

the value of x when b is 3 is x=-1

7 0
3 years ago
Solve logarithmic equation: ln a=4 HELP
Olin [163]
What’s the question lol
5 0
3 years ago
Suppose \nabla f (x,y) = 3 y \sin(xy) \vec{i} + 3 x \sin(xy)\vec{j}, \vec{f} = \nabla f(x,y), and c is the segment of the parabo
Anna11 [10]

I'll assume you're supposed to compute the line integral of \nabla f over the given path C. By the fundamental theorem of calculus,

\displaystyle\int_C\nabla f(x,y)\cdot\mathrm d\vec r=f(4,48)-f(1,3)

so evaluating the integral is as simple as evaluting f at the endpoints of C. But first we need to determine f given its gradient.

We have

\dfrac{\partial f}{\partial x}=3y\sin(xy)\implies f(x,y)=-3\cos(xy)+g(y)

Differentiating with respect to y gives

\dfrac{\partial f}{\partial y}=3x\sin(xy)=3x\sin(xy)+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C

and we end up with

f(x,y)=-3\cos(xy)+C

for some constant C. Then the value of the line integral is -3\cos192+3\cos3.

8 0
4 years ago
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