Question

14

Answer 1

Answer:

$m = -\frac{2}{3}$

Step-by-step explanation:

Given

$2x+3y=12$

$4x-3y=15$

Required

Slope of #1

$2x+3y=12$

Make y the subject

$3y = -2x + 12$

Divide through by 3

$y = -\frac{2}{3}x + \frac{12}{3}$

$y = -\frac{2}{3}x + 4$

An equation has the form:

$y = mx + c$

Where

$m = slope$

Compare $y = mx + c$ and $y = -\frac{2}{3}x + 4$

$m = -\frac{2}{3}$

Hence, the slope is $-\frac{2}{3}$