Answer:
Check the explanation
Step-by-step explanation:
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Answer:
Step-by-step explanation:
f(x) = x² – 8 and g(x) = 4-x
y=f(x) - g(x)
y=(x² – 8) - (4-x)
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
<h3>Step 1 - Find the gradient of 2x + 4y = 16</h3>
2x + 4y = 16
4y = 16 - 2x
y = 4 - 1/2x
gradient = -1/2
<h3>Step 2 - Find the Equation</h3>
y - y1 = m(x - x1)
m = gradient, (x1, y1) = (-2,2)
y - 2 = -1/2 (x + 2)
y - 2 = -1/2x - 1
y = -1/2x + 1 → ANSWER
Hope it helps!
Answer:
C
Step-by-step explanation:
