Answer:
m=1
Step-by-step explanation:
y2-y1/x2-x1
Answer:
a)120
b)6.67%
Step-by-step explanation:
Given:
No. of digits given= 6
Digits given= 1,2,3,5,8,9
Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be
6P3= 6!/3!
= 6*5*4*3*2*1/3*2*1
=6*5*4
=120
Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:
As the first and last digits can only be even
then the form of number can be
a)2n8 or
b)8n2
where n can be 1,3,5 or 9
4*2=8
so there can be 8 three-digit numbers with both the first digit and the last digit even numbers
And probability = 8/120
= 0.0667
=6.67%
The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !
Answer: 1,2,3 becuase they are all equivalent its just logic when you think abt it
Step-by-step explanation: 4 makes no sense
Answer:
It includes it because with out it there will be no center and it wouldn't be right. And with out it ever equation wont be proportional
Step-by-step explanation:
I really hope this helps Im just saying what I think is the answer it is my fault if you get the answer wrong <3
Answer:
y=154
Step-by-step explanation:
y/7=22
We simplify the equation to the form, which is simple to understand
y/7=22
Simplifying:
+ 0.142857142857y=22
We move all terms containing y to the left and all other terms to the right.
+ 0.142857142857y=+22
We simplify left and right side of the equation.
+ 0.142857142857y=+22
We divide both sides of the equation by 0.142857142857 to get y.
y=154
