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Vadim26 [7]
3 years ago
5

What is the greatest common factor for both terms: 24x + 8

Mathematics
1 answer:
Lyrx [107]3 years ago
3 0

24x=\boxed{2}\cdot\boxed{2}\cdot\boxed{2}\cdot3\cdot x\\\\8=\boxed{2}\cdot\boxed{2}\cdot\boxed{2}\\\\GCF(24x,\ 8)=\boxed{2}\cdot\boxed{2}\cdot\boxed{2}=8\\\\24x+8=8(3x+1)

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Arrange the fraction in asending and desending order 4/5 , 2/15 , 2/30​
Andrej [43]

Answer:

See below

Step-by-step explanation:

<u>Given fractions</u>

  • 4/5, 2/15, 2/30

<u>To arrange the fractions we need to bring them to common denominator</u>

  • LCM(5,15,30) = 30
  • 4/5 = 24/30
  • 2/15 = 4/30
  • 2/30

<u>In ascending order</u>

  • 2/30, 4/30, 24/30

<u>Reverse order</u>

  • 24/30, 4/30, 2/30

3 0
3 years ago
Please help I with give Brainiest if correct
padilas [110]

Answer:

  Perimeter of the rectangle  = 6 x +20

 Perimeter of the rectangle  = 0<em> x² + 6 x + 20</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the length of the rectangle = 2x +3

Given that the width of the rectangle = x +7

Perimeter of the rectangle   = 2(length + width)

<u>Step(ii):-</u>            

  Perimeter of the rectangle   = 2(length + width)

                                                  = 2(2 x +3 + x+7)

                                                 =  4x +6+2x+14

                                                 = 6 x +20        

<u><em>Final answer:-</em></u>

 Perimeter of the rectangle  = 6 x +20

 Perimeter of the rectangle  = o x² + 6 x + 20

7 0
3 years ago
Fill in the blank with the correct inequality symbol.<br> If x&gt;_5, then 4x __ 20
adoni [48]

Answer:

4x5 = 20

Step-by-step explanation:

Im not rlly sure at all but hope this helps :)

4 0
3 years ago
What is the value of x? 
Marrrta [24]
I dont know i just want coins lol
plus i just dont know

3 0
3 years ago
(2x^5y^2)(4xy^3)+(x^4y^4)(3x^2y)​
Korvikt [17]

Answer:

11x^6y^5

Step-by-step explanation:

Given: (2x^5y^2)(4xy^3)+(x^4y^4)(3x^2y)​

Use FOIL: 8x^6y^5 + 3x^6y^5

Combine like terms: 11x^6y^5

3 0
3 years ago
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