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lora16 [44]
2 years ago
12

PLEASE HELP WITH QUESTIONS 11-14 ASAP!!!!!!!!

Mathematics
1 answer:
zysi [14]2 years ago
3 0

Answer:

11) mean=2   12) median=2   13)range =4  

Step-by-step explanation:

11) the set is

0,0,1,1,1,2,2,2,2,2,3,3,3,4,4

so add all these which will give you 30 and then divide that by how many numbers are there in the set which there are 15, so 30 divided 15 =2

12) arrange numbers from smallest to largest and the number exactly in the middle is the median

13)biggest number-smallest number

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Write 3x^2-18x-6 in vertex form
Vedmedyk [2.9K]
The standard form of a quadratic equation is \displaystyle{ y=ax^2+bx+c, while the vertex form is:

                      y=a(x-h)^2+k, where (h, k) is the vertex of the parabola.

What we want is to write \displaystyle{ y=3x^2-18x-6 as y=a(x-h)^2+k

First, we note that all the three terms have a factor of 3, so we factorize it and write:

\displaystyle{ y=3(x^2-6x-2).


Second, we notice that x^2-6x are the terms produced by (x-3)^2=x^2-6x+9, without the 9. So we can write:

x^2-6x=(x-3)^2-9, and substituting in \displaystyle{ y=3(x^2-6x-2) we have:

\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11].

Finally, distributing 3 over the two terms in the brackets we have:

y=3[x-3]^2-33.


Answer: y=3(x-3)^2-33
6 0
3 years ago
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vladimir1956 [14]

Answer:

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Gnoma [55]

Answer:

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Volgvan

Answer:

Option 3

Step-by-step explanation:

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