Answer:
The solutions of the original equation are x=-5 and x=-2
Step-by-step explanation:
we have

Let

Rewrite the equation

Complete the square



rewrite as perfect squares

square root both sides




the solutions are
u=-2,u=1
<em>Alternative Method</em>
The formula to solve a quadratic equation of the form
is equal to
in this problem we have

so
substitute in the formula
the solutions are
u=-2,u=1
<em>Find the solutions of the original equation</em>
For u=-2
----> 
For u=1
----> 
therefore
The solutions of the original equation are
x=-5 and x=-2
Answer:
Step-by-step explanation:
or
Step-by-step explanation:
has:
1) amplitude=|a|
2) phase shift=b
3) period=2pi/c
d) vertical shift=d
--------------------------------------------------
You are given the amplitude is 2. This means a could either be 2 or -2.
You are given phase shift is -1/8. This means b is -1/8.
You are given the period is pi. So we need to solve pi=2pi/c.
pi=2pi/c
Dividing both sides by pi gives:
1=2/c
Multiply both sides by c gives:
c=2
The vertical shift is -2 so d=-2.
The equation could either be:
y=2cos(2(x-(-1/8)))-2
or
y=-2cos(2(x-(-1/8)))-2
Simplifying a little gives:
y=2cos(2x+1/4)-2
y=-2cos(2x+1/4)-2
Answer:
yes, I can help you do it.
Answer is number 2
F(3)= (3-1)^2+ 3(3)=4+9= 13 so the first option is wrong
F(-2)= (-2-1)^2+ 3(-2)= 9-6=3 third options is wrong
F(-15)= (-15-1)^2 +3(-15)= 256-45= 211 fourth option is wrong
The answer would be A, it has no solution