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RideAnS [48]
3 years ago
8

A scientist is studying the growth of a particular species of plant. He writes the following equation to show the height of the

plant f(n), in cm, after n days:
f(n) = 10(1.02)n

Part A: When the scientist concluded his study, the height of the plant was approximately 11.04 cm. What is a reasonable domain to plot the growth function? (4 points)

Part B: What does the y-intercept of the graph of the function f(n) represent? (2 points)
Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0

Answer:

PART A)

11.04 = 10(1.02)^n

1.104 = 1.02^n

ln 1.104 = ln 1.02^n

ln 1.104 = n ln 1.02

n = ln 1.104/ ln 1.02

n = 4.99630409516

4.99 can be rounded to 5.

So a reasonable domain would be 0 ≤ x < 5

PART B)

f(0) = 10(1.02)^0

f(0) = 10(1)

f(0) = 10

The y-intercept represents the height of the plant when they began the experiment.

Step-by-step explanation:

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VashaNatasha [74]

Answer:

Question 2. 12% of 650 = 78

Step-by-step explanation:

100% = 1 in decimal form.

This is because finding 100% of something is the same as multiplying it by 1:

E.g. 100% of 10=10,  10x1 = 10

Therefore to find a percentage of something, we simply need to multiply it by the decimal form of that percentage. For example, if we were finding 50% of 10 (half), 50% in decimal form is 0.5, 10x0.5 = 5

The percentage here is 12%, we can find the decimal form by dividing it by 100, 12/100 = 0.12

So, in order to find 12% of 650, we just need to multiply 650 by 0.12:

650x0.12 = 78

12% of 650 = 78

Hope this helped!

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3 years ago
Precal help if you could could you answer both. Me finishing this helps me graduate.
oee [108]

Exercise 1:

The easiest way to compute powers of complex numbers is to write them in the form

z = \rho e^{i\theta} = \rho(\cos(\theta)+i\sin(\theta))

In this form, you have

z^n = \rho^n e^{in\theta} = \rho^n(\cos(n\theta)+i\sin(n\theta))

The magnitude of the number is given by

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Exercise 2:

You simply have to compute the trigonometric function:

\cos\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{2}}{2},\quad \sin\left(-\dfrac{\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}

So, we have

z = \sqrt{2}\left(\dfrac{\sqrt{2}}{2} - i\dfrac{\sqrt{2}}{2}\right) = 1-i

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3 years ago
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