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Likurg_2 [28]
3 years ago
14

An Equation using t = 5

Mathematics
1 answer:
arlik [135]3 years ago
4 0
2t+2=12
here is ur answer
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Add 78, 139, and 14, and then divide by 44.
denpristay [2]

Answer:

5.24, 21/4, or 5 and 1/4

Step-by-step explanation:

78+139+14 = 231

231/44 = 5.25

Or 21/4 (improper fraction)

Or 5 and 1/4 (mixed number)

I'm not exactly sure what you were asking I hope that helps!

8 0
3 years ago
PLEASE HELP ILL MARK U THE BRAINLIEST IT IS URGENT AND ITS GEOMETRY DONT WASTE ANSWERS PLEASE
Verdich [7]

Answer:

∠Q = ∠U = 60°

Step-by-step explanation:

Construct the figure QSUT with your own dimensions as long as QR ≅ RU and SR ≅ RT , where R is the common midpoint.

I choose QR = 4 cm and SR = 5  cm

Then measure ∠Q and ∠U to check if they are equal.

I got that ∠Q = ∠U = 60° proving that;

∠Q ≅ ∠U

6 0
3 years ago
If 75% is 60 pounds what is the full cost
otez555 [7]
OK,  60 pounds is weight.... cost is money.... what the what?
3 0
3 years ago
A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la
SOVA2 [1]

Answer:

8\pi\text{ square cm}

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

S=2\pi rh

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

4^2 = (2r)^2 + h^2   ( see in the below diagram ),

16 = 4r^2 + h^2

16 - 4r^2 = h^2

\implies h=\sqrt{16-4r^2}

Thus, the surface area of the cylinder,

S=2\pi r(\sqrt{16-4r^2})

Differentiating with respect to r,

\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})

=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})

=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})

Again differentiating with respect to r,

\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})

For maximum or minimum,

\frac{dS}{dt}=0

2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0

-8r^2 + 16 = 0

8r^2 = 16

r^2 = 2

\implies r = \sqrt{2}

Since, for r = √2,

\frac{d^2S}{dt^2}=negative

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

S = 2\pi (\sqrt{2})(\sqrt{16-8})

=2\pi (\sqrt{2})(\sqrt{8})

=2\pi \sqrt{16}

=8\pi\text{ square cm}

4 0
3 years ago
How do you Simplify (y^12)^5
goldenfox [79]

Answer:

y^60

Step-by-step explanation:

(a^b)^b= a ^ b times b

12 times 5 is 60 so it's y^60

sorry my explaination is so complicated but im confident in the answer

8 0
3 years ago
Read 2 more answers
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