An Equation using t = 5

The parabola y = x² - 4 opens: A.) up B.) down C.) right D.) left

fomenos

Answer:

Up

Step-by-step explanation:

Here the easy rules to remember the orientation of the parabolas are

a) If x is squared it opens up or down. And its coefficient of { $x^{2}[tex] is negative it opens down.b) If y is squared it opens side ways right or left. It its coefficient of [tex]y^{2}$

Hence in our equation of parabola

$y = x^ 2-4$

x is squared and its coefficient is positive , hence it opens up towards positive y axis.

3 0

2 years ago

A construction company is planning to bid on a building contract. The bid costs the company $1400. The probability that the bid

liubo4ka [24]

Answer:

$3,000

Step-by-step explanation:

There two possible outcomes:

There is a 3/4 chance that the bid is rejected for a value of -$1,400

There is a 1/4 chance that the bid is accepted for a value of $17,600 - $1,400.

The expected value of the situation is:

$E = \frac{3}{4}*(-1,400)+\frac{1}{4}*(17,600-1,400)\\E=\$3,000$

The expected value is $3,000.

7 0

3 years ago

Find the value for “x”; 2 – 7x = -19

Law Incorporation [45]

Step-by-step explanation:

2+19=7x

21=7x

21÷7=7x÷7

3=x

..

4 0

3 years ago

What is this simplified

ki77a [65]

Answer:

84

Step-by-step explanation:

18816 divided by 224 is 84

4 0

3 years ago

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit

natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Let

a,b,c be the lengths of the sides of a triangle.

The area is given by:

$A=\sqrt{p(p-a)(p-b)(p-c)}$

where

p is half the perimeter

p= $\frac{a+b+c}{2}$

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(0)^{2}}$

$dAB=4\ units$

step 2

Find the distance BC

$d=\sqrt{(-2+3)^{2}+(1+2)^{2}}$

$d=\sqrt{(1)^{2}+(3)^{2}}$

$dBC=\sqrt{10}\ units$

step 3

Find the distance AC

$d=\sqrt{(-2-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$dBC=\sqrt{18}\ units$

step 4

$a=AB=4\ units$

$b=BC=\sqrt{10}\ units$

$c=AC=\sqrt{18}\ units$

Find the half perimeter p

p= $\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units$

Find the area

$A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}$

$A=\sqrt{5.7(1.7)(2.54)(1.46)}$

$A=\sqrt{35.93}$

$A=6\ units^{2}$

7 0

3 years ago