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3 years ago

An Equation using t = 5

Mathematics

1 answer:

arlik [135]3 years ago

4 0

2t+2=12
here is ur answer

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Add 78, 139, and 14, and then divide by 44.

denpristay [2]

Answer:

5.24, 21/4, or 5 and 1/4

Step-by-step explanation:

78+139+14 = 231

231/44 = 5.25

Or 21/4 (improper fraction)

Or 5 and 1/4 (mixed number)

I'm not exactly sure what you were asking I hope that helps!

8 0

3 years ago

PLEASE HELP ILL MARK U THE BRAINLIEST IT IS URGENT AND ITS GEOMETRY DONT WASTE ANSWERS PLEASE

Verdich [7]

Answer:

∠Q = ∠U = 60°

Step-by-step explanation:

Construct the figure QSUT with your own dimensions as long as QR ≅ RU and SR ≅ RT , where R is the common midpoint.

I choose QR = 4 cm and SR = 5 cm

Then measure ∠Q and ∠U to check if they are equal.

I got that ∠Q = ∠U = 60° proving that;

∠Q ≅ ∠U

6 0

3 years ago

If 75% is 60 pounds what is the full cost

otez555 [7]

OK, 60 pounds is weight.... cost is money.... what the what?

3 0

3 years ago

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

3 years ago

How do you Simplify (y^12)^5

goldenfox [79]

Answer:

y^60

Step-by-step explanation:

(a^b)^b= a ^ b times b

12 times 5 is 60 so it's y^60

sorry my explaination is so complicated but im confident in the answer

8 0

3 years ago

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