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2 years ago

Solve for x. 0.5x+78.2=287

Mathematics

1 answer:

Alona [7]2 years ago

8 0

Answer:

x =417.6

Step-by-step explanation:

0.5x+78.2=287

Subtract 78.2 from each side

0.5x+78.2-78.2=287-78.2

.5x =208.8

Divide each side by .5

.5x/.5 = 280.8/.5

x =417.6

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Please help me on this it’s due

olya-2409 [2.1K]

<h3>Answer: 5 cakes</h3>

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Explanation:

Let's start off converting the mixed number 12 & 1/4 to an improper fraction.

$a \frac{b}{c} = \frac{a*c+b}{c}\\\\12 \frac{1}{4} = \frac{12*4+1}{4}\\\\12 \frac{1}{4} = \frac{49}{4}\\\\$

Do the same for the other mixed number 2 & 1/3.

$a \frac{b}{c} = \frac{a*c+b}{c}\\\\2 \frac{1}{3} = \frac{2*3+1}{3}\\\\2 \frac{1}{3} = \frac{7}{3}\\\\$

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From here, we divide the two fractions. I converted them to improper fractions to make the division process easier.

$\frac{49}{4} \div \frac{7}{3} = \frac{49}{4} \times \frac{3}{7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{49\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 7\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 3}{4}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{21}{4}\\\\$

The last step is to convert that result to a mixed number.

$\frac{21}{4} = \frac{4*5+1}{4}\\\\\frac{21}{4} = \frac{4*5}{4}+\frac{1}{4}\\\\\frac{21}{4} = 4+\frac{1}{4}\\\\\frac{21}{4} = 5 \frac{1}{4}\\\\$

Note that 21/4 = 5.25 and 1/4 = 0.25 to help check the answer.

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Therefore, she can make 5 cakes. The fractional portion 1/4 is ignored since we're only considering whole cakes rather than partial ones.

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2 years ago

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lidiya [134]

Answer:

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Step-by-step explanation:

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3 years ago

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I can't say for sure this answer is 100% correct because I think more info is needed.

If your teacher is looking for the turning point, then that would be (4,10)

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If x was say the time in minutes and y was the temperature, then the turning point of y = -3(x-4)^3 + 10 could mean that at time 4 minutes (x = 4) the substance turns from liquid to solid (y = 10 degrees).

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Now, we can plot those two different pairs of coordinates for January and February on the graph.

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