B and (0,4)
because the 0 is the x intercept where it crosses
Answer:
34,220
Step-by-step explanation:
Because order doesn't matter, but the numbers can't be repeated, we need to find the number of combinations where 3 individual numbers can be chosen out of 60 possible numbers using the binomial coefficient:

Thus, Elias can make 34,220 unique 3-number codes given 60 different numbers.
Answer:
x^2+5x-6
a = 1 b = 5 and c = -6
Using the quadratic formula:
x = [-5 +- sq root (25 -4 * 1 *-6) ] / 2 * 1
x = [-5 +- sq root (49)] / 2
x = [-5 +- 7] / 2
x1 = 1
x2 = -6
Step-by-step explanation:
Answer:
It a simultaneous equation so the solution is 2
Step-by-step explanation:
Alright, so we plug (-2) in for x. (-2)^2 =4, and we can plug that in as 4(4)+(-2)+5. Next, 4*4=16, so we get 15+(-2)+5. After that, we get 15-2+5=18