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2 years ago

What is the slope of (-9, 8) and (3,- 12)

Mathematics

2 answers:

kkurt [141]2 years ago

8 0

-5/3. Uuhhhhhhhjjjuuuuu

earnstyle [38]2 years ago

3 0

Answer:

Your slope would be -5/3

Step-by-step explanation:

To find the slope from two points, you would use the formula y2-y1/x2-x1

In this case, the equation would look like -12-8/3-(-9)

-12 - 8 = -20

3 - (-9) = 12

-20/12 = -5/3

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Christian has a collection of 18 shark teeth. He identified them as 6 tiger shark teeth, 8 sand shark teeth, and the rest as bul

m_a_m_a [10]

Answer:

I'm well I can't include a model but I think I could explain it pretty well you see when you add the six tiger shark teeth and the eight sand tiger shark teeth together and compare that to the 18 that is 14 so they said the rest is well the rest is bull shark teeth so that is for so the ratio is 4 to 18 which means the 4 stands for the bull shark teeth to the whole amount of shark teeth

7 0

2 years ago

Read 2 more answers

-2 1/3-(-5) can someone help me

Masja [62]

Convert the mixed numbers to improper fractions then find the LCD and combine.
exact form: 8/3
decimal form: 2.6
mixed number form: 2 2/3

7 0

3 years ago

How to do: -8(1-a)=-7-(1-3a)

Fiesta28 [93]

In this question, you're solving for a.

Solve for a:

-8(1 - a) =-7 -(1 - 3a)

use the distributive property

-8 + 8a = -7 -(1 - 3a)

-8 + 8a = -7 - 1 + 3a

combine like terms

-8 + 8a = -8 + 3a

subtract 3a from both sides

-8 + 5a = -8

add 8 to both sides

5a = 0

divide both sides by 5

a = 0

7 0

2 years ago

50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle

aalyn [17]

Answer:

$EF=4\sqrt{3}$

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

$A_{\text{rect}}=8(6)=48\text{ cm}^2$

The area of the triangle is 1/4 of this. Therefore:

$\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2$

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

$\displaystyle 12=\frac{1}{2}(DE)(DF)$

Since DE = DF:

$24=DF^2$

Thus:

$DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE$

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

$(DE)^2+(DF)^2=(EF)^2$

Therefore:

$(2\sqrt6)^2+(2\sqrt6)^2=EF^2$

Square:

$24+24=EF^2$

Add:

$EF^2=48$

And finally, we can take the square root of both sides:

$EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}$

6 0

2 years ago

Read 2 more answers

Given the function f(x) = 2x+4 and the domain: {-1,0,1},determine the range

Svetlanka [38]

Answer:

f(x) = 2x + 4 domains {-1, 0, 1}

range {2, 4, 6}

(please mark brain if this helps and is correct)

Step-by-step explanation:

to solve f(x) to find the range you would want to input all the domain numbers in the equation f(x) to get the range of all the numbers you need

step 1: take the first domain number and input it into your equation where x is

ex: 2x + 4 [2(-1) + 4] = -2 + 4 = 2

step 2: add the second domain number and input it into your equation where x is

ex: 2x + 4 [2(0) + 4] = 0 + 4 = 4

step 3: add the last domain number and input it into your equation where x is

ex: 2x + 4 [2(1) + 4] = 2 + 4 = 6

Now we have determined what the range is

6 0

2 years ago