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Finger [1]
2 years ago
14

(2x+1)(x^2+8x-3) help standard form​

Mathematics
1 answer:
trapecia [35]2 years ago
6 0

Answer:

2x^3+17x^2+2x-3

Step-by-step explanation:

\left(2x+1\right)\left(x^2+8x-3\right)\\=2xx^2+2x\cdot \:8x+2x\left(-3\right)+1\cdot \:x^2+1\cdot \:8x+1\cdot \left(-3\right)\\=2x^3+17x^2+2x-3

In this equation, the variables were isolated to simplify the problem, following the order of operations. Negative-three either became an exponent or positive integer, 3, subtracted by a byproduct of the previous equation.

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Sita Rahim drove due north for 3 hours at 46 miles per hour. From the
Phantasy [73]

Answer:

224 miles

Step-by-step explanation:

What you would do is take the 3 hours times the 46 mph to get 138 miles.

3*46=138

Next, multiply the 2 hours by the 43 mph to get 86 miles.

2*43=86

Lastly, you're going to add the two.

138+86=224 miles.

6 0
3 years ago
Between t=10 and t=60 the acceleration is 0.4 calculate the speed when t=60​
Lisa [10]

Answer:

i dont understand

Step-by-step explanation:

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Hi!!! CLICK HERE!!! please answer this question well :)) i'll try to give brainliest when i can! thanks guys.
mylen [45]

Step-by-step explanation:

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6 0
2 years ago
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Can anyone help me with this equation?
liraira [26]

X equals 18. This might not be correct

4 0
3 years ago
Read 2 more answers
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

5 0
1 year ago
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