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Vaselesa [24]
2 years ago
13

Hell which one is true

Mathematics
1 answer:
nalin [4]2 years ago
5 0

Answer:

sjshdsedhbehbeh i dont know

Step-by-step explanation:

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-3+9-27+81-243+729. Using the sigma notation to write the given sum
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Answer:

546

Step-by-step explanation:

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Please help me<br> Evaluate 7+2^3<br> Answer:________
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9^...................

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6) find the volume of the cone
Molodets [167]

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I'm pretty sure it's C/80.

Step-by-step explanation:

Have a beautiful dayyy!

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3 years ago
Explain in your own words what domain and range mean
a_sh-v [17]
A domain is an input that you put in an equation(x). A range is an output (y) that is the result of a certain input.

Hope this helps and please mark as brainliest!
3 0
3 years ago
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A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a
natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, .   .   .  , x₂₃ be the actual data observed by the student

The sample means  = x₁  +  x₂  +  .   .   .  , x₂₃ / 23

= \frac{x_1 +x_2 +...x_2_3}{23}

= 2.3hr

⇒\sum xi =2.3 \times 23 = 52.9hrs

let x₁ , x₂, .   .   .  , x₂₃  arranged in ascending order

Then x₂₃ was 10  and has been changed to 14

i.e x₂₃ increase to 4

Sample mean  = \frac{x_1 +x_2 +...x_2_3}{23}

\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47

therefore, the new sample mean is 2.47

2) For the old data set

the median is x_1_2(th) values

[\frac{n +1}{2} ]^t^h value

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = [{x_1_2]^t^h value remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)

The new sample standard sample deviation is calculated as

= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)

Now, when we compare (1) and (2)  the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)²  ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0
3 years ago
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