Question

what is the coordinate of the vertex of the parabola y-2=1/12(x+10) a. ( 10,-2) b. (-10,2) c. (-2,10) d. (2.-10)

Answer 1

Answer:

$y-a= c(x-b)^2$

With the vertex $V= (b,a)$

We see that b = -10 and a = 2 and then the vertes wuld be:

$V= (-10,2)$

And the best option is:

b. (-10,2)

Step-by-step explanation:

For this problem we have the following function:

$y-2 = \frac{1}{2} (x+10)$

And if we compare this expression with the general expression for a parabola given by:

$y-a= c(x-b)^2$

With the vertex $V= (b,a)$

We see that b = -10 and a = 2 and then the vertes wuld be:

$V= (-10,2)$

And the best option is:

b. (-10,2)