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Leno4ka [110]
3 years ago
6

What is the y-intercept of the line? 1 1/2 -2 0

Mathematics
1 answer:
Sliva [168]3 years ago
6 0

Answer: its 1

Step-by-step explanation:

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slamgirl [31]
30? I think thats the answer


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3 years ago
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Can someone help me solve these problems?
Goshia [24]

Answer:

Step-by-step explanation:

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8 0
2 years ago
Write with fractional exponents.
marusya05 [52]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

y^\frac{2}{3}

»»————- ★ ————-««  

Here’s why:  

  • We are supposed to rewrite a radical expression as an expression with fraction exponents.

⸻⸻⸻⸻

The rule for a fraction exponent is:

a^{\frac{x}{y}}=\sqrt[y]{a^x}\\\\\\\huge\boxed{\frac{\text{Power}}{\text{Root}}}

⸻⸻⸻⸻

We are given the expression of \sqrt[3]{y^2}.

⸻⸻⸻⸻

\boxed{\text{Rewriting the expression:}}\\\\\sqrt[3]{y^2}\\\\\text{The '3' is the root and the '2' is the power.}\\\\\rightarrow \sqrt[3]{y^2} \\\\\rightarrow {y^{\frac{2}{3}}

⸻⸻⸻⸻

\text{The answer should be: } \boxed{y^\frac{2}{3} }

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

7 0
3 years ago
A square part of side 20 meters has a footpath along the boundary of width 10 meters . Find the area of path
qaws [65]

Answer:

Answer: 84 meters squared. (i.e. 84m^2).

Step-by-step explanation:

Area of the path = total area of path and plot - plot area only

First, let’s find the area of the plot:

20m x 20m = 400m^2

The path is 1m wide and runs all the way around, so, it describes an ‘outer square’ of 22m x 22m (2 x 1m larger because there are 1m of the path on each side).

The area of this ‘outer square’ is equivalent to the ‘total area of path and plot’

22m x 22m = 484m^2

So:

Area of the path = total area of path and plot - plot area only

= 484 - 400 = 84m^2

4 0
3 years ago
The points (0, 5) and (4, 13) lie on the graph of a linear function. What is the rate of change of the function?
Viefleur [7K]
The rate of change is the slope of this line
m = (y2 - y1)/(x2 - x1) = (13 - 5)/(4 - 0) = 8/4 = 2
6 0
3 years ago
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