Question

Please help I need you guys12 \leqslant 42" alt="2x + 12 \leqslant 42" align="absmiddle" class="latex-formula">


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Answer 1

ANSWER

My answer is in the photo above

Answer 2

Answer:

$\displaystyle \large{x \leqslant 15}$

Step-by-step explanation:

We are given the Inequality:

$\displaystyle \large{2x + 12 \leqslant 42}$

To solve an Inequality, solve it like an equation: We isolate x-term.

First, subtract 12 both sides.

$\displaystyle \large{2x + 12 - 12 \leqslant 42 - 12} \\ \displaystyle \large{2x \leqslant 30}$

Then divide both sides by 2.

$\displaystyle \large{ \frac{2x}{2} \leqslant \frac{30}{2} }$

Divide the like term. 2 divides 2 = 1; 2 divides 30 = 15.

$\displaystyle \large{ \frac{ \cancel{2}x}{ \cancel{2}} \leqslant \frac{ \cancel{30}}{ \cancel{2}} } \\ \displaystyle \large{ \frac{ 1x}{ 1} \leqslant \frac{15}{1} }$

Generally, we do not recommend writing 1 as a denominator as we would just cancel 1 anyways.

That goes the same to 1x which we can simplify to x.

$\displaystyle \large \boxed{ x \leqslant 15}$

Let me know if you have any questions!