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dangina [55]
3 years ago
5

I need helpPlssssssssssssss

Mathematics
1 answer:
Semmy [17]3 years ago
8 0

The correct answer would be B because .47 is bigger than 42/100 or .42

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A student answers 160 of 200 questions on an exam correctly. What percent of the questions did he answer correctly?
Alexandra [31]

Dive correct answers by total questions:

160/200 = 0.80

Multiply by 100 to get percent:

0.80 x 100 = 80%

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3 years ago
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I really need help on this question!!!! Please
zhannawk [14.2K]

It's saying <em>d </em><em> </em>÷ <em>h </em><em> </em>= <em>x.</em>

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In what time will sum of money double itself at 5% per annum?​
klemol [59]

Step-by-step explanation:

Mr.Josol : what will be the height of the ball after 2 seconds?

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3 years ago
It takes 20 minutes for 5 people to paint 5 walls.
Sergio039 [100]

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7 0
3 years ago
A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4
skad [1K]

Answer:

a) \bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401

b) The sample deviation is calculated from the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s=0.0036

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma =0.00319

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

And if we replace we got:

\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s=0.0036

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma =0.00319

3 0
3 years ago
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