Width=20.108 yrd and Length=43.216 yrd
Step-by-step explanation:
Let width = w
Length =3+2w
Area = 869 yrd^2
We need to find length and width of rectangle.
The formula used is:
Putting values:
Using quadratic equation to find value of width w:
a=2, b=3 and c=-869
Since width can't be negative so, width w=20.108
Length will be: L=3+2w = 3+2(20.108)=3+40.216=43.216
So, Width=20.108 yrd and Length=43.216 yrd
Keywords: Area of rectangle
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Answer:b=7
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
2(3b−1)=40
(2)(3b)+(2)(−1)=40(Distribute)
6b+−2=40
6b−2=40
Step 2: Add 2 to both sides.
6b−2+2=40+2
6b=42
Step 3: Divide both sides by 6.
6b/6=42/6
b=7
3(x-1)^2 +2
This is your answer in vertex form, your h and k values are the vertex. Solving the function by using b/2a, we get that h is 1. ( in the equation 3 is your a, 6 is b and 5 is c.). ( 6/2(3)) = 1. We can then plug in 1 as x into the original equation and get positive 2 ( 3(1)^2 -6(1) +5) = 3-6+5 = 2. This is your vertex. In the function, your a value will always stay the same as this is your shrink or stretch. In this case, a is 3 so it will go outside the parenthesis. Put that all together and you get the function above.
Hope this helps :)
Answer:
The answer would be - 11.
Step-by-step explanation:
9 + 8 = 17
17 - 6 = 11.
4 - 5 = 4 + - 5 = - 1
11(- 1) = 11 × - 1 = - 11
Therefor, your answer would be - 11.
Hope this helps!
