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3 years ago

Turtles tutles turtles turtles

Mathematics

2 answers:

Paul [167]3 years ago

7 0

Answer:

hey

Step-by-step explanation:

I like ya cut g XD

lesantik [10]3 years ago

4 0

Answer:

TURTLES TURTLES bro!!!!!!!

Step-by-step explanation:

my pet turtles name is godzilla. that deserves the crown i think.

You might be interested in

F(x)= x squared -3x + 2 divided by 3x squared + 9 x -12

VashaNatasha [74]

Answer:

=(x-2)/3(x+4)

Step-by-step explanation:

F(x)=x²-3x+2/3x²+9x-12

Using mid term break formula

=x²-2x-x+2/3(x²+3x-4)

=x(x-2)-1(x-2)/3(x²+4x-x-4)

=(x-2)(x-1)/3{x(x+4)-1(x+4)}

=(x-2)(x-1)/3(x-1)(x+4)

Cancelling (x-1)

We get

=(x-2)/3(x+4)

Hope it helps :)

6 0

4 years ago

Using the given information, give the vertex form equation of each parabola.

Amanda [17]

Answer:

The equation of parabola is given by : $(x-4) = \frac{-1}{3}(y+3)^{2}$

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:( $\frac{47}{12}$ ,-3)

The general equation of parabola is given by.

$(x-h)^{2} = 4p(y-k)$ , When x-componet of focus and Vertex is same

$(x-h) = 4p(y-k)^{2}$ , When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

For value of p:

p= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

p= $\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}$

p= $\sqrt{(\frac{1}{12})^{2}}$

p= $\frac{1}{12}$ and p= $\frac{-1}{12}$

Since, Focus is left side of the vertex,

p= $\frac{-1}{12}$ is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p= $\frac{-1}{12}$

$(x-h) = 4p(y-k)^{2}$

$(x-4) = 4(\frac{-1}{12})(y+3)^{2}$

$(x-4) = \frac{-1}{3}(y+3)^{2}$

8 0

3 years ago

Find the least positive angle measurement that is coterminal with -230

Mila [183]

I think the correct one is C. 130

8 0

3 years ago

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

3 years ago

Oduvanchick [21]

Answer: p = 30 q = 30 (if not touching edge of hexagon but if it is touching edge one of the pairs) then p or q = 120 and p and q = 30

Step 1) Sum of an interior angle of a polygon = 720 degree where n = 6 as 6 exterior sides = (n-2) * 180 = (6-2) * 180 = 4 * 180 = 720 degree Where the measure of each angle of a hexagon = 720/ 6 = 120 degree Step 2) Then show 3 angle letter names = 180 degree Step 3) Angle name letters + 2 angle (other two names letters inside within triangle) add up to 180 degree Step 3) State since triangle name (of all letters within one triangle) is Isosceles Step 4) Triangle (state same triangle letters with number 2 in front) = 180 - 120 = 60 then state triangle (letter name) / 2 = 30 degrees obviously the 120 and 60 differentiates if not a hexagon to a pentagon if not a hexagon = (3 *180) / 5 = 108 then due to isosceles (180 - 108)/ 2 = 72/2 = 36 degree for a pentagon or 30 degree each for p + q for a hexagon etc

6 0

3 years ago