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3 years ago

9

Joyce uses 3/10 bag of chocolate chips for each batch of cookies she makes. What is the least number of batches Joyce can make i

f she has to open a second bag of chocolate chips?

1 answer:

Ugo [173]3 years ago

7 0

Answer:

6 batches is the least amount.

Step-by-step explanation:

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yanalaym [24]

Answer:

System is given below

Step-by-step explanation:

Let (applicable to all three lines below)
Hard candy = x kg with price $1.60/kg
Gummy worms = y kg with price $2.20/kg
Total weight = 50 kg with mixed price $1.75/kg

<u>Required equations:</u>

x + y = 50 total weight
1.60x + 2.20y = 50*1.75 total price

=========================================

<u><em>Note</em></u><em>. It says don't solve but the solution below for those who is interested to know the answer.</em>

<u>Simplify the second equation and solve by substitution x = 50 - y:</u>

1.6(50 - y) + 2.2y = 87.5
80 - 1.6y +2.2y = 87.5
0.6y = 7.5
y = 7.5/0.6
y = 12.5

<u>Find the value of x:</u>

x = 50 - 12.5 = 37.5

<u>Hard candy</u> = 37.5 kg and <u>gummy worms</u> = 12.5 kg

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3 years ago

What are the first 6 terms for this arithmetic equation?

Ipatiy [6.2K]

Answer:

3, - 2, - 7, - 12, - 17, - 22

Step-by-step explanation:

To find the first 6 terms substitute n = 1, 2, 3, 4, 5 into the formula, that is

t(1 + 1) = t(1) - 5 ⇒ t(2) = 3 - 5 = - 2

t(2 + 1) = t(2) - 5 ⇒ t(3) = - 2 - 5 = - 7

t(3 + 1) = t(3) - 5 ⇒ t(4) = - 7 - 5 = - 12

t(4 + 1) = t(4) - 5 ⇒ t(5) = - 12 - 5 = - 17

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3 years ago

This equation which is || = -10 ?

sesenic [268]

Answer:

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Step-by-step explanation:

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3 years ago

Please help me with this question.

Evgen [1.6K]

Answer:

$\purple{ \boxed{\frac{d^{2} y}{dx ^{2} } = \frac{132}{ {x}^{13} } }}$

Step-by-step explanation:

$y = \frac{1}{ {x}^{11} } \\ y = {x}^{ - 11} \\ \frac{dy}{dx} = \frac{d}{dx} {x}^{ - 11} \\ \frac{dy}{dx} = - 11{x}^{ - 11 - 1} \\ \frac{dy}{dx} = - 11{x}^{ - 12} \\ \\ \frac{d}{dx} \bigg(\frac{dy}{dx} \bigg) = \frac{d}{dx} ( - 11 {x}^{ - 12} ) \\ \\ \frac{d^{2} y}{dx ^{2} } = - 11\frac{d}{dx} ( {x}^{ - 12} ) \\ \\ \frac{d^{2} y}{dx ^{2} } = - 11( - 12{x}^{ - 13} ) \\ \\ \frac{d^{2} y}{dx ^{2} } = 132{x}^{ - 13} \\ \\ \huge \red{ \boxed{\frac{d^{2} y}{dx ^{2} } = \frac{132}{ {x}^{13} } }}$

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3 years ago